4 Variable Karnaugh Map (Part 3)

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September 5, 2014
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Neso Academy
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4 Variable Karnaugh Map (Part 3)

Transcript

let's move to the another example in the four variable k-map the function f with four variables let's say X Y Z and W is there and the min terms are 1 5 7 1 5 7 9 11 13 9 11 13 and 15 so here we are having the min terms as M 1 M 5 m 7m 9 m xi m 13 and M 15 now we have to reduce this by using the key map we can do it by the boolean algebra also but ... Read More

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