# 2003 AIME II problem 15 (part 1) | Math for fun and glory | Khan Academy | Summary and Q&A

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January 13, 2011
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2003 AIME II problem 15 (part 1) | Math for fun and glory | Khan Academy

## TL;DR

The video explains how to simplify a polynomial by recognizing a pattern in squaring polynomials, using x^3 + x^2 + x + 1 as an example.

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### Q: How is p(x) initially defined and what variables are introduced?

p(x) is defined as 24x^24 + Σ(24 - j)(x^(24 - j) + x^(24 + j)) for j = 1 to 23. Variables like a_k, b_k, and z_k are introduced, indicating real numbers, coefficients, and distinct roots.

### Q: What is the aim of finding the sum of the absolute values of the imaginary parts of the square of the roots?

The aim is to find m + n + p, where m, n, and p are integers and p is not divisible by the square of any prime, by summing the absolute values of the imaginary parts of the square of the roots of p(x).

### Q: How does the video simplify the polynomial p(x)?

The video reorganizes p(x) from highest degree term to lowest degree term, revealing a pattern of increasing and decreasing coefficients. It then rewrites p(x) in a simplified form as x(x^23 + x^22 + ... + x + 1)^2.

### Q: What is the significance of recognizing the pattern in squaring polynomials?

Recognizing the pattern allows for simplification of p(x) and reveals the coefficients of the simplified form, which are crucial for solving the problem of finding the sum of the absolute values of the imaginary parts of the square of the roots.

## Summary & Key Takeaways

• The video introduces a polynomial, p(x), and defines several variables and equations related to its roots and coefficients.

• The polynomial p(x) is rewritten in a simplified form, revealing a pattern in the coefficients.

• A pattern in squaring polynomials is explained and used to simplify p(x) further.

• The video concludes with the significance of the simplified form for solving the problem at hand.