# Analyzing mistakes when finding extrema (example 1) | AP Calculus AB | Khan Academy | Summary and Q&A

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August 4, 2017
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Analyzing mistakes when finding extrema (example 1) | AP Calculus AB | Khan Academy

## TL;DR

Pamela mistakenly concludes that a function has a relative extremum at x = 2 based solely on the fact that the derivative is zero at that point.

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### Q: What is Pamela's mistake in her analysis of finding the relative extremum?

Pamela's mistake is in step three, where she concludes that the function has a relative extremum at x = 2 based solely on the fact that the derivative is zero at that point.

### Q: Why is it necessary to test the derivative on either side of the critical point?

Testing the derivative on either side of the critical point is necessary to determine if the function has a positive or negative slope before and after the critical point, which is crucial in identifying a relative extremum.

### Q: Can a function have a zero derivative at a point without having a relative extremum?

Yes, there can be cases where the derivative is zero at a point, but the function does not have a relative extremum. This occurs when the slope changes from positive to negative or vice versa before and after the critical point.

### Q: What is the correct way to identify a relative extremum?

To identify a relative extremum, one must test the function's derivative on either side of the critical point. If the slope changes from positive to negative (minimum) or negative to positive (maximum), then the function has a relative extremum at that point.

## Summary & Key Takeaways

• Pamela correctly takes the derivative of the function and finds that h'(x) = 3(x-2)^2.

• She correctly identifies that h'(x) = 0 when x = 2, which is a critical point.

• However, she mistakenly concludes that h has a relative extremum at x = 2 without further analysis.

• To determine if there is a relative extremum, it is necessary to test the derivative on either side of the critical point.