Problem No.10 Based on Value of Function - Functions - Diploma Maths - II

TL;DR

Given the function f(x) = x^2 + 2x + 5, find the value of x for which f(x) = f(2x+1).

Transcript

click the bell icon to get latest videos from akira hello friends in this video we are going to see problem number 10 based on value of function so let us start with the problem if f of X is equal to X square plus 2x plus 5 find X for which f of X is equal to F of 2x plus 1 now this numerical is a little bit different in last type we have covered t... Read More

Key Insights

• ☺️ The video discusses a problem related to finding the value of x for which two functions are equal.
• ❓ The given function is f(x) = x^2 + 2x + 5.
• ❓ By substituting 2x+1 into f(x) and simplifying, a quadratic equation is obtained.
• ☺️ The quadratic equation is further simplified to (X + 1)² = 0.
• ☺️ The solution to the quadratic equation is x = -1.
• ❓ This solution satisfies the condition f(x) = f(2x+1).
• 🗂️ Dividing each term of the quadratic equation by 3 simplifies it to (x + 1)² = 0.

Questions & Answers

Q: What is the problem discussed in the video?

The problem in the video involves finding the value of x for which f(x) is equal to f(2x+1).

Q: What is the given function?

The given function is f(x) = x^2 + 2x + 5.

Q: How do you find f(2x+1)?

To find f(2x+1), substitute 2x+1 into the given function and then simplify the expression.

Q: What type of equation is obtained from simplifying the expression?

From the simplification process, a quadratic equation is obtained.

Summary & Key Takeaways

• The content discusses a problem involving finding the value of x for which the function f(x) is equal to f(2x+1).

• The given function is f(x) = x^2 + 2x + 5.

• By substituting the expression 2x+1 into the function, expanding and simplifying, a quadratic equation is obtained.