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Sodium Hydroxide + Sulfuric Acid - Acid Base Neutralization Reaction

July 3, 2020
by
The Organic Chemistry Tutor
YouTube video player
Sodium Hydroxide + Sulfuric Acid - Acid Base Neutralization Reaction

TL;DR

Learn how to write the balanced and net ionic equations for the reaction between sodium hydroxide and sulfuric acid.

Transcript

in this tutorial we're going to talk about how to write the balanced molecular equation and the net ionic equation of the reaction between sodium hydroxide and sulfuric acid so let's begin the chemical formula of sodium hydroxide is naoh and the chemical formula for sulfuric acid is h2 so4 now both of these are in the aqueous phase which means that... Read More

Key Insights

  • 💪 Sodium hydroxide (NaOH) is a strong base, while sulfuric acid (H2SO4) is a strong acid.
  • 😥 The reaction between NaOH and H2SO4 is a neutralization reaction, resulting in a pH of around 7.
  • ❓ The balanced molecular equation for the reaction is 2NaOH + H2SO4 -> Na2SO4 + 2H2O.
  • 😑 The net ionic equation, after eliminating spectator ions, is H+ + OH- -> H2O.
  • 💦 Sodium sulfate (Na2SO4) is soluble in water, hence written as (aq) in the equations.
  • 🪐 The coefficients in the net ionic equation can be simplified by dividing by 2.

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Questions & Answers

Q: What are the products of the reaction between sodium hydroxide and sulfuric acid?

The products are sodium sulfate (Na2SO4) and water (H2O). NaOH combines with H+ to form water, and Na pairs up with SO4 to form sodium sulfate.

Q: Why is the sodium sulfate written as Na2SO4 in the balanced equation?

Sodium (Na) has a +1 charge and sulfate (SO4) has a -2 charge. To balance the charges, two sodium ions are needed for every sulfate ion, resulting in Na2SO4.

Q: What is the difference between a balanced molecular equation and a net ionic equation?

A balanced molecular equation shows the complete formula of all the reactants and products. A net ionic equation only includes the ions taking part in the reaction, excluding the spectator ions that appear unchanged on both sides.

Q: How do you write the net ionic equation for the reaction?

To write the net ionic equation, separate the reactants and products into their ionic forms. Then, eliminate the spectator ions that appear the same on both sides. The resulting equation shows the essential ions involved in the reaction.

Summary & Key Takeaways

  • Sodium hydroxide (NaOH) and sulfuric acid (H2SO4) react to form sodium sulfate (Na2SO4) and water (H2O).

  • The reaction is a neutralization reaction between a strong acid (H2SO4) and a strong base (NaOH).

  • The balanced molecular equation is 2NaOH + H2SO4 -> Na2SO4 + 2H2O, and the net ionic equation is H+ + OH- -> H2O.


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