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RC Circuit (7 of 8) Discharging a Capacitor, Time Constant, Voltage, Current, Worked Example

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December 18, 2016
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Step by Step Science
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RC Circuit (7 of 8) Discharging a Capacitor, Time Constant, Voltage, Current, Worked Example

TL;DR

Solving capacitor discharge problems with specific values, calculating voltage at different time intervals.

Transcript

okay in this video I think we're going to go over through go over an example problem for discharging a capacitor and this is a situation that we have this 470 micro farad capacitor we've previously been charged by 12 volt sources 12 volts across the capacitor I went to discharge a capacitor to a 57 K ohm resistor alright so now these are the three ... Read More

Key Insights

  • ⌛ Time constant in an RC circuit is a crucial parameter for capacitor discharge calculations.
  • ⌛ Voltage across a capacitor decreases exponentially with time.
  • ⌛ Voltage at specific time intervals can be calculated using the exponential decay equation.
  • ⌛ Fully discharging a capacitor requires around five time constants.
  • ❓ Physics principles of capacitance and resistance are applied in practical circuit analysis.
  • ❓ Understanding capacitor discharge provides insight into energy storage and release mechanisms.
  • 🦻 Calculation of time constants and capacitor voltage aids in circuit design and analysis.

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Questions & Answers

Q: How is time constant calculated for a resistor and capacitor combination?

The time constant is found by multiplying the resistance and capacitance values, giving the time it takes for the voltage to decrease significantly in an RC circuit.

Q: What is the equation used to calculate voltage across a capacitor with respect to time?

The equation is V(t)=V(initial) * e^(-t/RC), where V(t) is the voltage at time t, V(initial) is the initial voltage, e is Euler's number, t is time, R is resistance, and C is capacitance.

Q: How does the voltage across a capacitor change after one time constant?

After one time constant, the voltage across the capacitor will be around 36.8% of its initial voltage, with the equation V=V(initial) * 0.368.

Q: Why is it considered that a capacitor is fully discharged after five time constants?

Although a capacitor never fully reaches zero voltage, after five time constants, it is practically considered fully discharged due to the exponential decay nature.

Summary & Key Takeaways

  • Example problem of discharging a capacitor with specific values.

  • Calculating voltage across the capacitor after one time constant.

  • Determining voltage after 20 seconds and time to fully discharge.


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