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Derivatives of sec(x) and csc(x) | Derivative rules | AP Calculus AB | Khan Academy

July 21, 2016
by
Khan Academy
YouTube video player
Derivatives of sec(x) and csc(x) | Derivative rules | AP Calculus AB | Khan Academy

TL;DR

The video explains how to find the derivatives of secant and cosecant functions using the quotient rule.

Transcript

  • [Voiceover] In a previous video we used the quotient rule in order to find the derivatives of tangent of x and cotangnet of x. And what I what to do in this video is to keep going and find the derivatives of secant of x and cosecant of x. So let's start with secant of x. The derivative with respect to x of secant of x. Well, secant of x is the sa... Read More

Key Insights

  • ☺️ Secant x is equivalent to 1 over cosine x, and cosecant x is equivalent to 1 over sine x.
  • ☺️ The quotient rule can be used to find the derivatives of both secant x and cosecant x.
  • 😑 The derivatives can be expressed in terms of other trigonometric functions, such as tangent x, cotangent x, and secant x.

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Summary & Key Takeaways

  • The derivative of secant of x can be found by applying the quotient rule, resulting in sine x over cosine squared x.

  • The derivative of cosecant of x can also be found using the quotient rule, giving negative cosine x over sine squared x.

  • Both derivatives can also be expressed in terms of other trigonometric functions, with secant of x equal to tangent x times secant x, and cosecant of x equal to negative cotangent x times cosecant x.


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