IIT JEE Diameter Slope

TL;DR
The slope of the line joining two points on a parabola can be expressed as 2/r.
Transcript
Let A and B be two distinct points on the parabola y squared is equal to 4x. If the axis of the parabola touches a circle of radius r, having AB as its diameter, then the slope of the line joining A and B can be. So let's draw this. So let me draw my axes here. That's my y-axis. And here is my x-axis. And then the parabola y squared is equal to 4x ... Read More
Key Insights
- 🤗 The parabola y^2 = 4x is a symmetrical graph that opens to the right.
- 👈 The diameter of a circle touching the x-axis can be formed using two points on the parabola as its endpoints.
- 😥 The coordinates of the midpoint of the diameter can be found by averaging the coordinates of the two points.
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Questions & Answers
Q: How is the parabola y^2 = 4x represented on a graph?
The parabola y^2 = 4x is symmetric and opens to the right. It can be divided into two parts: y = 2√x and y = -2√x.
Q: What is the relationship between point A, point B, and the radius of the circle?
The sum of the x-coordinates of points A and B is equal to the radius of the circle.
Q: How can the coordinates of the midpoint of AB be calculated?
The coordinates of the midpoint are found by taking the average of the x-coordinates and the average of the y-coordinates of points A and B.
Q: What is the slope of the line joining points A and B?
The slope of the line is equal to 2/r, where r is the radius of the circle.
Summary & Key Takeaways
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The parabola y^2 = 4x is graphed and points A and B are chosen on the parabola.
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The diameter of a circle, with AB as its diameter and touching the x-axis, is constructed.
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The coordinates of the midpoint of AB are found, which is equal to r, the radius of the circle.
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The slope of the line joining points A and B is determined to be 2/r.
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