Energy dissipation across two resistors in series example

TL;DR

A student builds a circuit with two resistors in series and analyzes the energy dissipated at each resistor over time.

Transcript

• [Instructor] A student builds a circuit with a battery and two resistors in series. The resistance of R2 is double the resistance of R1. Below is the graph of the energy lost at R1 over time. So that's this graph. Which of the following shows the energy lost at R2 over time in terms of E1. We have these four choices here. So pause this video and ... Read More

Key Insights

• ❓ Current in a series circuit remains constant throughout.
• ⌛ The energy dissipated over time in a resistor can be calculated using the equation: energy dissipated = current^2 * resistance * time.
• ❓ The energy dissipated at a resistor is directly proportional to its resistance.
• ☠️ The slope of the energy vs. time graph represents the rate of energy dissipation.

Questions & Answers

Q: How are the two resistors connected in the circuit?

The two resistors are connected in series, with the current passing through both resistors sequentially.

Q: How are the resistances of the two resistors related?

The resistance of the second resistor is double the resistance of the first resistor.

Q: What is the equation for power in a circuit?

Power is equal to the energy dissipated over time, which can be expressed as the change in voltage across a resistor multiplied by the current flowing through it.

Q: Why does the energy dissipated at the second resistor have twice the value of the first resistor at time T1?

The energy dissipated at the second resistor is twice the value because it has double the resistance, leading to a higher energy dissipation.

Summary & Key Takeaways

• A circuit is constructed with a battery and two resistors in series.

• The resistance of the second resistor is twice that of the first resistor.

• The energy dissipated at each resistor over time is determined.