Sodium Hydroxide + Sulfuric Acid - Acid Base Neutralization Reaction

TL;DR

Learn how to write the balanced and net ionic equations for the reaction between sodium hydroxide and sulfuric acid.

Transcript

in this tutorial we're going to talk about how to write the balanced molecular equation and the net ionic equation of the reaction between sodium hydroxide and sulfuric acid so let's begin the chemical formula of sodium hydroxide is naoh and the chemical formula for sulfuric acid is h2 so4 now both of these are in the aqueous phase which means that... Read More

Key Insights

• 💪 Sodium hydroxide (NaOH) is a strong base, while sulfuric acid (H2SO4) is a strong acid.
• 😥 The reaction between NaOH and H2SO4 is a neutralization reaction, resulting in a pH of around 7.
• ❓ The balanced molecular equation for the reaction is 2NaOH + H2SO4 -> Na2SO4 + 2H2O.
• 😑 The net ionic equation, after eliminating spectator ions, is H+ + OH- -> H2O.
• 💦 Sodium sulfate (Na2SO4) is soluble in water, hence written as (aq) in the equations.
• 🪐 The coefficients in the net ionic equation can be simplified by dividing by 2.

Summary & Key Takeaways

• Sodium hydroxide (NaOH) and sulfuric acid (H2SO4) react to form sodium sulfate (Na2SO4) and water (H2O).

• The reaction is a neutralization reaction between a strong acid (H2SO4) and a strong base (NaOH).

• The balanced molecular equation is 2NaOH + H2SO4 -> Na2SO4 + 2H2O, and the net ionic equation is H+ + OH- -> H2O.