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MTEL Math Practice Test: 9-11

December 16, 2009
by
Khan Academy
YouTube video player
MTEL Math Practice Test: 9-11

TL;DR

Solve math problems involving ratios, number lines, and finding the least common multiple.

Transcript

We're on problem nine. Use the problem below to answer the question that follows. Given that 100 milliliters is equal to approximately 0.4 cups, 205 milliliters is equal to approximately how many cups? So we could set up a little ratio here. We could say 100 milliliters is to 0.4 cups as 200 milliliters-- I'll write the cups here-- is to how many c... Read More

Key Insights

  • 😵 Ratios can be solved using cross multiplication to find unknown quantities.
  • 🫥 Number lines can help visualize distances and find values between given endpoints.
  • ✋ The least common multiple is found by identifying the common prime factors and multiplying the highest exponent of each.

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Questions & Answers

Q: How can we find the number of cups that 205 milliliters is equal to?

By setting up a ratio using 100 milliliters to 0.4 cups and solving for x, we find that 205 milliliters is equal to 2.05 cups (or 205% of 0.4).

Q: What is the value of point P on the number line between 0.003 and 0.004?

To find the value of point P, we divide the entire distance between 0.003 and 0.004 (0.001) by 8, which gives us 0.000125. Multiplying this by 2, we get 0.00025, which, when added to 0.003, gives us the answer of 0.00325.

Q: How do we determine the smallest possible total number of textbooks that is divisible by 12, 15, and 18?

To find the least common multiple, we break down each number into its prime factors. By multiplying the highest exponent of each prime factor, we get the smallest total number of textbooks, which is 180.

Summary & Key Takeaways

  • Problem 9 involves solving a ratio to determine the number of cups that 205 milliliters is equal to.

  • In problem 10, a number line is used to find the value of point P, which is two increments past 0.003.

  • Problem 11 requires finding the least common multiple of 12, 15, and 18 as the smallest possible total number of textbooks.


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