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Projectile on an incline | Two-dimensional motion | Physics | Khan Academy

June 16, 2011
by
Khan Academy
YouTube video player
Projectile on an incline | Two-dimensional motion | Physics | Khan Academy

TL;DR

Solving a complex physics problem involving projectile motion on an incline with given velocities and angles.

Transcript

What I want to do in this video is tackle a problem that would be considered pretty difficult for most first-year physics students. And you, frankly, probably wouldn't be expected to solve a problem like this in most first-year physics class. Or if you're in an advanced or honors class you might be expected or it might be a bonus problem. But it's ... Read More

Key Insights

  • 🚥 Projectile motion problems on inclines require considering both horizontal and vertical displacement simultaneously.
  • 🍳 The velocity can be broken down into horizontal and vertical components using trigonometry.
  • 🚥 The relationship between vertical and horizontal displacement is determined using the tangent function.

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Questions & Answers

Q: What makes this projectile motion problem more complex compared to traditional problems?

This problem requires considering both horizontal and vertical displacement simultaneously, as the vertical displacement depends on the point of landing on the incline.

Q: How can we break down the velocity into horizontal and vertical components?

The horizontal velocity component is equal to the total velocity times the cosine of the angle with the horizontal, while the vertical velocity component is equal to the total velocity times the sine of the angle with the horizontal.

Q: How is the relationship between vertical and horizontal displacement determined?

The tangent of the angle of inclination of the incline is equal to the vertical displacement divided by the horizontal displacement. This relationship is derived using trigonometric functions.

Q: How are the vertical and horizontal displacements calculated?

The vertical displacement is calculated using the initial vertical velocity, time, acceleration due to gravity, and the formula derived in previous videos. The horizontal displacement is calculated using the horizontal velocity and time.

Summary & Key Takeaways

  • The video discusses a difficult physics problem involving projectile motion on an incline.

  • The problem requires considering both horizontal and vertical displacement simultaneously, unlike traditional projectile motion problems.

  • Key steps in solving the problem include breaking down the velocity into vertical and horizontal components, using trigonometry to determine the relationship between vertical and horizontal displacement, and solving for the vertical and horizontal displacements.


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