Problem on Finding Diameter of Link Stock - Stress and Strain - Strength of Materials

TL;DR

Calculate the diameter of a crane chain link stock to withstand a maximum load of 50 kilo newton with a permissible tensile stress of 75 mega pascal.

Transcript

hello students here in this video we are going to see a problem in which we have to calculate the diameter of a link stop and for that here we have a question a coil chain of a crane is required to carry a maximum load of 50 kilo newton as shown in figure the diagram is given in this diagram we have a chain which is this oval section here and it is... Read More

Key Insights

• 🍻 The problem involves calculating the diameter of a chain link stock to withstand a specific load and tensile stress.
• 😃 The formula for stress solution, sigma t = p/area, is used to determine the diameter.
• 🇦🇪 The given load, permissible tensile stress, and diameter calculations are converted from different units for accurate results.

Questions & Answers

Q: What is the maximum load the chain needs to carry?

The maximum load is 50 kilo newton, which is equivalent to 15x10^3 newton.

Q: What is the permissible tensile stress in the link material?

The permissible tensile stress is 75 mega pascal, which is equivalent to 75 newton per mm square.

Q: How is the diameter of the link stock calculated?

The formula used is sigma t = p/area, where sigma t is the tensile stress, p is the load, and area is pi/4 times the diameter squared.

Q: What is the calculated diameter of the link stock?

The diameter of the link stock is calculated to be 29.13 mm.

Summary & Key Takeaways

• A coil chain of a crane carrying a maximum load of 50 kilo newton needs to determine the diameter of the link stock.

• The permissible tensile stress in the link material should not exceed 75 mega pascal.

• Using the formula for stress solution, the diameter is calculated to be 29.13 mm.