Numerical Based on Decay Constant Problem 16 - Nuclear Chemistry & Radioactivity

TL;DR

Learn how to calculate the half-life of a radioisotope by analyzing data on the decay of 3/4th of the original amount over 60 minutes.

Transcript

click the bell icon to get latest videos from akira hello friends in the previous topic we have discussed about the numerical based on the decay constant problem number 15 and here we see we are going to talk about how to solve this problem number 16 so let us talk about it in this topic so friends here is a cushion that is a 3 by 4 of the original... Read More

Key Insights

• ❓ 3/4th of the original amount of a radioisotope decays over 60 minutes.
• 🛟 By knowing the decay percentage, the remaining amount, decay constant, and half-life can be calculated.
• 🙅 The decay constant is found by using the formula lambda = 2.303 / t log10(N₀ / N).
• 🛟 The half-life period is calculated using the formula t₁/₂ = 0.693 / lambda.
• 🇦🇪 The unit of the decay constant in this problem is minute inverse.
• 🛟 The unit of the half-life period in this problem is minutes.
• 🛟 This method can be applied to calculate the half-life of any radioisotope.

Questions & Answers

Q: How is the decay constant calculated in this problem?

The decay constant is calculated by using the formula lambda = 2.303 / t log10(N₀ / N), where t is the time of change (60 minutes), N₀ is the original amount (100%), and N is the remaining amount (25%).

Q: What is the unit of the decay constant?

The unit of the decay constant in this problem is minute inverse, as the unit of time used is minutes.

Q: What formula is used to calculate the half-life period?

The formula used to calculate the half-life period is t₁/₂ = 0.693 / lambda, where lambda is the decay constant found in the calculation (0.0231 minute inverse).

Q: Can this method be applied to calculate the half-life of any radioisotope?

Yes, this method can be applied to calculate the half-life of any radioisotope as long as the relevant data on decay is provided.

Summary & Key Takeaways

• A 3/4th decay of a radioisotope's original amount occurs over 60 minutes.

• By knowing the percentage of the original amount left (25%), the decay constant and half-life can be calculated.

• The decay constant is found to be 0.0231 minutes inverse, and the half-life is calculated as 30 minutes.