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Derivative of x^x^x - Logarithmic Differentiation of Exponential Functions

April 23, 2017
by
The Organic Chemistry Tutor
YouTube video player
Derivative of x^x^x - Logarithmic Differentiation of Exponential Functions

TL;DR

This video explains the process of finding the derivative of the function x raised to the x raised to the x.

Transcript

in this video we're going to focus on finding the derivative of x raised to the x raised to the x so how can we go about doing that what steps do we need to take the first thing that we should do is set it equal to y and that's step one in the next step we need to take the natural log of both sides and the reason why we want to do that is because t... Read More

Key Insights

  • 🌆 Setting the function equal to y and taking the natural log helps simplify the expression before differentiation.
  • 😀 Differentiating ln y involves using the chain rule and the derivative of the inside function.
  • ☺️ The product rule and power rule are used to differentiate x ln x and ln ln x, respectively.

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Questions & Answers

Q: What is the first step in finding the derivative of x raised to the x raised to the x?

The first step is to set the function equal to y and then take the natural log of both sides to simplify the expression.

Q: How does the natural log property allow us to move the exponent to the front?

The property states that ln a squared is equal to 2 ln a. By applying this property, the exponent of x can be moved to the front in the equation ln y = x raised to the x times ln x.

Q: Why do we need to take the natural log of both sides again?

Taking the natural log of both sides one more time allows us to simplify the expression further and make it easier to differentiate.

Q: How is the product rule used to differentiate x ln x?

The product rule for natural log functions is applied, which states that ln a times b is equal to ln a + ln b. This allows us to separate x raised to the x and ln x in the differentiation process.

Summary & Key Takeaways

  • The first step is to set the function equal to y and then take the natural log of both sides.

  • By using the property of natural logarithms, the exponent can be moved to the front, resulting in ln y = x raised to the x times ln x.

  • Differentiation is done by applying the product rule for natural log functions and the derivative of x ln x, followed by simplification.


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