How to Determine the Power Required - Properties of Fluid - Fluid Mechanics 1

TL;DR

This video explains how to calculate the force and power required to maintain a certain fluid flow velocity.

Transcript

hello friends here in this video we will see how to calculate power required let's read what is the question given here a flat plate of area 1.5 into 10 raised to 6 mm square is pulled with a speed of 0.4 meter per second relative to another plate located at a distance of 0.15 mm from it full stop find the force and power required to maintain this ... Read More

Key Insights

• ✊ The video focuses on calculating the force and power required to maintain fluid flow between two plates.
• ❎ Conversion of units, such as area from mm square to meter square, is necessary.
• 👮 Shear stress is obtained using Newton's law of viscosity.
• ✖️ The force required is found by multiplying shear stress by area.
• ✊ The power required is calculated by multiplying force by velocity.
• ✊ The units for power are watts (W), which is equal to joules per second (J/s).
• 💐 The force required to maintain the fluid flow in this problem is 400 N.

Questions & Answers

Q: What is the formula for shear stress in fluid flow?

Shear stress is given by the equation tau = mu * du/dy, where tau is shear stress, mu is dynamic viscosity, du is the change in velocity, and dy is the change in distance.

Q: How do you convert the area from mm square to meter square?

To convert an area from mm square to meter square, multiply it by 10^-6. In this case, the area of 1.5 million mm square becomes 1.5 meter square.

Q: What is the value of shear stress in this problem?

By plugging in the given values, the shear stress is calculated to be 266.67 N/m^2 (or Pa).

Q: What is the equation for calculating power required in fluid flow?

The equation for power required is P = F * v, where P is power, F is force, and v is velocity.

Summary & Key Takeaways

• A flat plate with an area of 1.5 million mm square is pulled at a speed of 0.4 m/s relative to another plate located 0.15 mm away.

• The fluid separating the plates has a viscosity of one poise.

• The video shows how to calculate the force and power required to maintain this fluid flow.