Products
Features
YouTube Video Summarizer
Summarize YouTube videos
Web & PDF Highlighter
Highlight web pages & PDFs
Chat with PDF
Ask any PDF questions with AI
Ask AI Clone
Chat with your highlights & memories
Audio Transcriber
Transcribe audio files to text
Glasp Reader
Read and highlight articles
Kindle Highlight Export
Export your Kindle highlights
Idea Hatch
Hatch ideas from your highlights
Integrations
Obsidian Plugin
Notion Integration
Pocket Integration
Instapaper Integration
Medium Integration
Readwise Integration
Snipd Integration
Hypothesis Integration
Apps & Extensions
Chrome Extension
Safari Extension
Edge Add-ons
Firefox Add-ons
iOS App
Android App
Discover
Discover
Ideas
Discover new ideas and insights
Articles
Curated articles and insights
Books
Book recommendations by great minds
Posts
Essays and notes from readers
Quotes
Inspiring quotes collection
Videos
Curated videos and summaries
Explore Glasp
Glasp Newsletter
Weekly insights and updates
Glasp Talk
Interview series with great minds
Glasp Blog
Latest news and articles
Glasp Use Cases
Learn how others use Glasp
Build & Support
Glasp API
Access Glasp's API for developers
MCP Connector
Connect Glasp to Claude & ChatGPT
Community
Glasp Reddit Community
Students
Student discount and benefits
FAQs
Frequently Asked Questions
AboutPricing
DashboardLog inSign up

Prove that if a/b = c/d = e/f then (a^3b + 2c^2e - 3ae^2f)/(b^4 + 2d^2f - 3bf^3) = (ace)/(bdf)

2.6K views
•
September 5, 2022
by
The Math Sorcerer
YouTube video player
Prove that if a/b = c/d = e/f then (a^3b + 2c^2e - 3ae^2f)/(b^4 + 2d^2f - 3bf^3) = (ace)/(bdf)

TL;DR

Prove the equality of ratios using algebraic manipulation from a 1960s book.

Transcript

hey we're going to do a proof we're told that if a over b is equal to c over d and that's equal to e over f shoot that this is true so why does it say shoe instead of show um i don't actually know i should have done some research on that before making this video but i'm just sitting here doing some math and i've got a book with me it's a really old... Read More

Key Insights

  • 🥶 Referencing older algebraic books can provide interesting and challenging problems for mathematical enthusiasts.
  • 😑 Expressing ratios as variables can aid in simplifying algebraic proofs.
  • 😑 Careful manipulation and simplification of expressions are essential steps in proving mathematical statements.

Install to Summarize YouTube Videos and Get Transcripts

Explore YouTube Video Summarizer or Get YouTube Transcript Extractor

Questions & Answers

Q: What is the significance of the book "Higher Algebra" by Holland Knight in the video?

The book "Higher Algebra" by Holland Knight serves as the reference for the presented algebraic problem, emphasizing its importance in providing challenging algebra exercises.

Q: How does the narrator approach proving the equality of ratios a/b, c/d, and e/f?

The narrator sets the ratios as variable k = a/b = c/d = e/f and then expresses a, c, and e in terms of k, leading to a detailed algebraic manipulation to prove the equality.

Q: Why does the narrator express the numerators a, c, and e as variables in the proof?

By expressing the numerators as variables, namely a, c, and e, the narrator simplifies the manipulation process to illustrate the equality of the given ratios algebraically.

Q: How does the narrator simplify the final expression to prove the equality of the ratios?

The narrator carefully simplifies the expressions involving a, c, e, and the denominators to show that these ratios are indeed equal to ace divided by bdf, completing the proof.

Summary & Key Takeaways

  • The video discusses proving the equality of ratios a/b, c/d, and e/f by expressing the numerators as variables a, c, and e.

  • The narrator carefully manipulates the expressions to show that the given ratios are indeed equal to ace divided by bdf.

  • The proof involves writing down the expressions, simplifying them, and showing that they are equal to the expected result.


Read in Other Languages (beta)

English

Share This Summary 📚

Summarize YouTube Videos and Get Video Transcripts with 1-Click

Download browser extensions on:

Try YouTube Summary with ChatGPT & Claude or YouTube Transcript Generator

Explore More Summaries from The Math Sorcerer 📚

How to Find the Curvature using the Cross Product Formula for r(t) = ti + t^2j + (t^2/2)k thumbnail
How to Find the Curvature using the Cross Product Formula for r(t) = ti + t^2j + (t^2/2)k
The Math Sorcerer
Prove that Every Integer is Even or Odd thumbnail
Prove that Every Integer is Even or Odd
The Math Sorcerer
How to Sketch a Vector Valued Function and Find Orientation and Rectangular Form thumbnail
How to Sketch a Vector Valued Function and Find Orientation and Rectangular Form
The Math Sorcerer
How to Solve a Bernoulli Differential Equation Step-by-Step thumbnail
How to Solve a Bernoulli Differential Equation Step-by-Step
The Math Sorcerer
Proving two Spans of Vectors are Equal Linear Algebra Proof thumbnail
Proving two Spans of Vectors are Equal Linear Algebra Proof
The Math Sorcerer
Learn How to Express Sums in Summation Notation thumbnail
Learn How to Express Sums in Summation Notation
The Math Sorcerer

Summarize YouTube Videos and Get Video Transcripts with 1-Click

Download browser extensions on:

Try YouTube Summary with ChatGPT & Claude or YouTube Transcript Generator

Apps & Extensions

  • Chrome Extension
  • Safari Extension
  • Edge Add-ons
  • Firefox Add-ons
  • iOS App
  • Android App

Key Features

  • YouTube Video Summarizer
  • Web & PDF Summarizer
  • Web & PDF Highlighter
  • Chat with PDF
  • Ask AI Clone
  • Audio Transcriber
  • Glasp Reader
  • Kindle Highlight Export
  • Idea Hatch

Integrations

  • Obsidian Plugin
  • Notion Integration
  • Pocket Integration
  • Instapaper Integration
  • Medium Integration
  • Readwise Integration
  • Snipd Integration
  • Hypothesis Integration

More Features

  • APIs
  • MCP Connector
  • Blog & Post
  • Embed Links
  • Image Highlight
  • Personality Test
  • Quote Shots

Company

  • About us
  • Blog
  • Community
  • FAQs
  • Job Board
  • Newsletter
  • Pricing
Terms

•

Privacy

•

Guidelines

© 2026 Glasp Inc. All rights reserved.