Products
Features
YouTube Video Summarizer
Summarize YouTube videos
Web & PDF Highlighter
Highlight web pages & PDFs
Chat with PDF
Ask any PDF questions with AI
Ask AI Clone
Chat with your highlights & memories
Audio Transcriber
Transcribe audio files to text
Glasp Reader
Read and highlight articles
Kindle Highlight Export
Export your Kindle highlights
Idea Hatch
Hatch ideas from your highlights
Integrations
Obsidian Plugin
Notion Integration
Pocket Integration
Instapaper Integration
Medium Integration
Readwise Integration
Snipd Integration
Hypothesis Integration
Apps & Extensions
Chrome Extension
Safari Extension
Edge Add-ons
Firefox Add-ons
iOS App
Android App
Discover
Discover
Ideas
Discover new ideas and insights
Articles
Curated articles and insights
Books
Book recommendations by great minds
Posts
Essays and notes from readers
Quotes
Inspiring quotes collection
Videos
Curated videos and summaries
Explore Glasp
Glasp Newsletter
Weekly insights and updates
Glasp Talk
Interview series with great minds
Glasp Blog
Latest news and articles
Glasp Use Cases
Learn how others use Glasp
Build & Support
Glasp API
Access Glasp's API for developers
MCP Connector
Connect Glasp to Claude & ChatGPT
Community
Glasp Reddit Community
Students
Student discount and benefits
FAQs
Frequently Asked Questions
AboutPricing
DashboardLog inSign up

Derivative of inverse tangent | Taking derivatives | Differential Calculus | Khan Academy

May 1, 2014
by
Khan Academy
YouTube video player
Derivative of inverse tangent | Taking derivatives | Differential Calculus | Khan Academy

TL;DR

The video explains how to find the derivative of the inverse tangent function using trigonometric identities.

Transcript

We already know that the derivative with respect to x of tangent of x is equal to the secant of x squared, which is of course the same thing of one over cosine of x squared. Now what we wanna do in this video, like we've done in the last few videos, is figure out what the derivative of the inverse function of the tangent of x is, or in particular, ... Read More

Key Insights

  • 🌆 The derivative of the inverse tangent function can be found by setting y equal to inverse tangent of x.
  • 🟰 The chain rule is applied to find the derivative of tangent of y, which is equal to x.
  • ❣️ The derivative of y with respect to x is expressed as cosine of y squared.

Install to Summarize YouTube Videos and Get Transcripts

Explore YouTube Video Summarizer or Get YouTube Transcript Extractor

Questions & Answers

Q: What is the derivative of the inverse tangent function?

The derivative of the inverse tangent function is one over one plus x squared.

Q: How is the derivative derived using trigonometric identities?

The video uses the Pythagorean identity and the relationship between sine, cosine, and tangent to derive the derivative expression.

Q: Why is it important to express the derivative as a function of x?

Expressing the derivative as a function of x allows for easy calculation and understanding of the rate of change of the inverse tangent function.

Q: What is the chain rule and how is it applied in this context?

The chain rule allows for the calculation of the derivative of a composite function. In this case, it is used to find the derivative of the tangent of y, which is a function of x.

Summary & Key Takeaways

  • The video discusses finding the derivative of the inverse tangent function by setting y equal to inverse tangent of x.

  • After applying the chain rule and simplifying, the derivative of y with respect to x is found to be cosine of y squared.

  • By expressing cosine of y squared as a function of tangent of y, the derivative can be written as one over one plus x squared.


Read in Other Languages (beta)

English

Share This Summary 📚

Summarize YouTube Videos and Get Video Transcripts with 1-Click

Download browser extensions on:

Try YouTube Summary with ChatGPT & Claude or YouTube Transcript Generator

Explore More Summaries from Khan Academy 📚

Dividing quadratics by linear expressions with remainders | Algebra 2 | Khan Academy thumbnail
Dividing quadratics by linear expressions with remainders | Algebra 2 | Khan Academy
Khan Academy
Life in traffic question 5 thumbnail
Life in traffic question 5
Khan Academy
Worked example: Interpreting potential energy curves of diatomic molecules | Khan Academy thumbnail
Worked example: Interpreting potential energy curves of diatomic molecules | Khan Academy
Khan Academy
Calculating integral with shell method | AP Calculus AB | Khan Academy thumbnail
Calculating integral with shell method | AP Calculus AB | Khan Academy
Khan Academy
Converting percent to decimal and fraction | Decimals | Pre-Algebra | Khan Academy thumbnail
Converting percent to decimal and fraction | Decimals | Pre-Algebra | Khan Academy
Khan Academy
Classical Japan during the Heian Period | World History | Khan Academy thumbnail
Classical Japan during the Heian Period | World History | Khan Academy
Khan Academy

Summarize YouTube Videos and Get Video Transcripts with 1-Click

Download browser extensions on:

Try YouTube Summary with ChatGPT & Claude or YouTube Transcript Generator

Apps & Extensions

  • Chrome Extension
  • Safari Extension
  • Edge Add-ons
  • Firefox Add-ons
  • iOS App
  • Android App

Key Features

  • YouTube Video Summarizer
  • Web & PDF Summarizer
  • Web & PDF Highlighter
  • Chat with PDF
  • Ask AI Clone
  • Audio Transcriber
  • Glasp Reader
  • Kindle Highlight Export
  • Idea Hatch

Integrations

  • Obsidian Plugin
  • Notion Integration
  • Pocket Integration
  • Instapaper Integration
  • Medium Integration
  • Readwise Integration
  • Snipd Integration
  • Hypothesis Integration

More Features

  • APIs
  • MCP Connector
  • Blog & Post
  • Embed Links
  • Image Highlight
  • Personality Test
  • Quote Shots

Company

  • About us
  • Blog
  • Community
  • FAQs
  • Job Board
  • Newsletter
  • Pricing
Terms

•

Privacy

•

Guidelines

© 2026 Glasp Inc. All rights reserved.