Derivative of inverse tangent | Taking derivatives | Differential Calculus | Khan Academy

TL;DR
The video explains how to find the derivative of the inverse tangent function using trigonometric identities.
Transcript
We already know that the derivative with respect to x of tangent of x is equal to the secant of x squared, which is of course the same thing of one over cosine of x squared. Now what we wanna do in this video, like we've done in the last few videos, is figure out what the derivative of the inverse function of the tangent of x is, or in particular, ... Read More
Key Insights
- 🌆 The derivative of the inverse tangent function can be found by setting y equal to inverse tangent of x.
- 🟰 The chain rule is applied to find the derivative of tangent of y, which is equal to x.
- ❣️ The derivative of y with respect to x is expressed as cosine of y squared.
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Questions & Answers
Q: What is the derivative of the inverse tangent function?
The derivative of the inverse tangent function is one over one plus x squared.
Q: How is the derivative derived using trigonometric identities?
The video uses the Pythagorean identity and the relationship between sine, cosine, and tangent to derive the derivative expression.
Q: Why is it important to express the derivative as a function of x?
Expressing the derivative as a function of x allows for easy calculation and understanding of the rate of change of the inverse tangent function.
Q: What is the chain rule and how is it applied in this context?
The chain rule allows for the calculation of the derivative of a composite function. In this case, it is used to find the derivative of the tangent of y, which is a function of x.
Summary & Key Takeaways
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The video discusses finding the derivative of the inverse tangent function by setting y equal to inverse tangent of x.
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After applying the chain rule and simplifying, the derivative of y with respect to x is found to be cosine of y squared.
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By expressing cosine of y squared as a function of tangent of y, the derivative can be written as one over one plus x squared.
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