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Problem on Efficiency - Simple Machines - Engineering Mechanics

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•
April 11, 2022
by
Ekeeda
YouTube video player
Problem on Efficiency - Simple Machines - Engineering Mechanics

TL;DR

Calculate the efficiency of a machine with a given law and velocity ratio, using the formula for mechanical advantage.

Transcript

hello friends in this video we will see a problem in which we have to calculate efficiency if the law of machine is given so let us read the question here a certain machine has a law p is equal to 0.025 w plus 20 newton with velocity ratio equal to 16 calculate its efficiency if load is of one kilo newton now this is the problem which we have i'll ... Read More

Key Insights

  • 🥳 The problem involves calculating the efficiency of a machine based on its given law and velocity ratio.
  • 🥳 The formula for efficiency is load/effort * velocity ratio, where the load is given as 1000 newton and the effort is determined from the given law.
  • ❓ The efficiency is found to be 37.03% by substituting the values into the efficiency formula.

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Questions & Answers

Q: What is the formula used to calculate efficiency in this problem?

The efficiency is calculated using the formula for mechanical advantage divided by velocity ratio: load/effort * velocity ratio.

Q: What is the given law of the machine?

The law of the machine is p = 0.025w + 20 newton, where p represents effort and w represents load.

Q: How is the efficiency calculated when the load is given as 1000 newton?

The efficiency is calculated by substituting the load (1000 newton), effort (45 newton from the given law), and velocity ratio (60) into the efficiency formula: load/effort * velocity ratio.

Q: What is the efficiency of the machine in this problem?

The efficiency of the machine is found to be 37.03% after calculating it using the given values and the efficiency formula.

Summary & Key Takeaways

  • A certain machine has a given law: p = 0.025w + 20 newton, with a velocity ratio of 60.

  • The problem requires calculating the efficiency of the machine when the load is 1000 newton.

  • By substituting the given values into the formula for efficiency (load/effort * velocity ratio), the efficiency is found to be 37.03%.


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