2nd Numerical of Most Economical Section - Flow through Open Channels - Applied Hydraulics

TL;DR

This content explains how to calculate the slope of a circular channel's bed for maximum water velocity.

Transcript

hello students today we are going to solve second numerical of most economical section question is given as the rate of flow of water through a circular channel of diameter 0.6 meter is 150 liter per second find the slope of the bed of the channel for maximum velocity take this constant c equals to 16. now we have to find here the slope of the bed ... Read More

Key Insights

• 🤒 The rate of flow of water through a circular channel needs to be converted to cubic meters per second for further calculations.
• ✖️ The hydraulic mean depth is calculated using 0.3 multiplied by the diameter of the circular channel.
• ✖️ The wetted perimeter of a circular channel is found by multiplying the diameter with the theta value obtained in radians.
• 🤭 The discharge can be determined using the formula q = ac√mi, where a is the area, c is a constant, m is the hydraulic mean depth, and i is the slope.

Questions & Answers

Q: What is the first step in solving the numerical?

The first step is to convert the given rate of flow from liters per second to cubic meters per second.

Q: How is the hydraulic mean depth calculated?

The hydraulic mean depth is calculated by multiplying the constant 0.3 with the diameter of the circular channel.

Q: How do we find the wetted perimeter for a circular channel?

The wetted perimeter is obtained by multiplying the diameter of the channel with the value of theta obtained in radians.

Q: What is the formula used to calculate the discharge?

The discharge is calculated using the formula q = ac√mi, where q is the discharge, a is the area, c is a constant, m is the hydraulic mean depth, and i is the slope.

Summary & Key Takeaways

• Given the rate of water flow through a circular channel, diameter, and a constant, the goal is to find the slope of the channel's bed.

• Using the given values, the depth of flow, hydraulic mean depth, wetted perimeter, and area of the channel are calculated.

• Finally, the discharge and slope of the channel are determined using the derived values.