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Problem No 12 on Beta Function - Beta and Gamma Function - Engineering Mathematics - 2

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March 31, 2022
by
Ekeeda
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Problem No 12 on Beta Function - Beta and Gamma Function - Engineering Mathematics - 2

TL;DR

Learn how to evaluate integrals using the properties of beta and gamma function.

Transcript

hey students so here we have a question on beta and gamma function where we will evaluate the integral by using the different properties of beta and gamma function and the definition of beta function so for you we have integration from 0 to infinity x raised to it in bracket 1 minus x raised to 6 whole upon 1 plus x raised to 24 dx now the question... Read More

Key Insights

  • 🔨 The gamma function and beta function are essential tools in evaluating integrals.
  • 🍉 The beta function's definition can be used to evaluate integrals with all algebraic terms and a limit from 0 to infinity.
  • 🆘 Manipulating the integral to match the beta function's definition helps in determining the values of m and n.

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Questions & Answers

Q: What are the properties of the gamma function and beta function?

The gamma function has one exponential term and one algebraic term, while the beta function has two algebraic terms. Both functions can be used for integration from 0 to infinity.

Q: How do you evaluate integrals using the beta function?

To evaluate an integral with all algebraic terms and a limit from 0 to infinity, you can use the definition of the beta function. The definition states that if the integral is of the form x^(m-1)/(1+x^(m+n)), it can be represented as beta(m, n).

Q: How do you match the integral form with the beta function definition?

To match the integral form with the beta function definition, you need to manipulate the integral. Multiply the numerator by x^8 to get x^(8) - x^(14) and divide the numerator separately with the denominator. This will give you two separate integrals.

Q: How do you use the properties of beta function to evaluate the integral?

By applying the properties of beta function, you can determine the values of m and n. In the given example, the values are m=9 and n=15 for the first integral, and m=15 and n=9 for the second integral. Using the property that beta(m,n) = beta(n,m), you can subtract the two beta values to get the final result of 0 for the integral.

Summary & Key Takeaways

  • The content discusses the process of evaluating integrals using beta and gamma functions.

  • It explains the definitions of gamma and beta functions and their formulas for integration from 0 to infinity.

  • The content demonstrates the step-by-step process of evaluating a specific integral using the beta function.


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