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Problem no 6 Based on Inverse Hyperbolic Function

236 views
•
March 31, 2022
by
Ekeeda
YouTube video player
Problem no 6 Based on Inverse Hyperbolic Function

TL;DR

In this video, the instructor solves a unique problem on inverse hyperbolic functions by simplifying a given term and using trigonometric and hyperbolic function formulas.

Transcript

click the bell icon to get latest videos from akira hello students so after covering so many problems on inverse hyperbolic function I'm gonna take one more problem on inverse hyperbolic function and let me tell you that this problem is different than the previous problems and here we are gonna learn a new concept about the inverse hyperbolic funct... Read More

Key Insights

  • ❓ Inverse hyperbolic functions can be simplified and expanded using trigonometric and hyperbolic function formulas.
  • 🥳 Comparing real and imaginary parts of complex numbers can help in solving equations.
  • 🆘 Substituting values and using mathematical identities can help derive the desired result.

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Questions & Answers

Q: What is the goal of the problem in this video?

The goal is to prove that the value of a variable, B, is equal to log(2 + √3).

Q: How does the instructor begin to solve the problem?

The instructor starts by simplifying the given term and expanding the hyperbolic cos and sine functions using trigonometric and hyperbolic function formulas.

Q: How does the instructor find the real and imaginary parts of the equation?

The instructor multiplies and combines terms to separate the real and imaginary parts of the equation.

Q: How does the instructor solve for the value of B?

The instructor concludes that B is equal to A and substitutes this value into the equation, eventually simplifying it to log(2 + √3), which is the desired result.

Summary & Key Takeaways

  • The instructor simplifies a given term involving inverse hyperbolic functions.

  • The hyperbolic cos and sine functions are expanded using trigonometric and hyperbolic function formulas.

  • The instructor separates the real and imaginary parts of the equation and solves for the values of the variables.


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