Solving equations by graphing: intro | Algebra 2 | Khan Academy | Summary and Q&A

2.0K views
July 22, 2019
by
Khan Academy
YouTube video player
Solving equations by graphing: intro | Algebra 2 | Khan Academy

TL;DR

Use the graph of an equation and its intersection with a second equation to approximate the solutions to the original equation.

Install to Summarize YouTube Videos and Get Transcripts

Key Insights

  • 😥 Graphing equations and finding the intersection points is an effective method to approximate solutions.
  • 👈 The x-values at the intersection points of two graphs represent solutions to the original equation.
  • #️⃣ The number of times two graphs intersect indicates the number of solutions to the equation.

Transcript

Read and summarize the transcript of this video on Glasp Reader (beta).

Questions & Answers

Q: How can graphing be used to approximate solutions to equations?

By graphing the given equation and setting it equal to another equation, we can find the x-values where the graphs intersect, which give us the approximate solutions to the original equation.

Q: What does it mean if two graphs intersect at a certain point?

If two graphs intersect at a specific point, it means that the corresponding x-value and y-value satisfy both equations simultaneously, indicating a solution to the original equation.

Q: How can we determine the number of solutions to an equation using graphing?

By graphing the equation and counting the number of times the graph intersects with a specific line, we can identify the number of solutions to the equation.

Q: Are the approximate solutions obtained through graphing always exact?

No, the approximate solutions obtained through graphing may not be exact, but they provide a close approximation to the actual solutions of the equation.

Summary & Key Takeaways

  • By graphing the equation y = 3/2^x and setting it equal to the right-hand side, y = 5, we can find the approximate solution for 3/2^x = 5, which is x ≈ 4.

  • Graphing the equation y = x^3 - 2x^2 - x + 1 and setting it equal to y = -1 helps determine the number of solutions for x^3 - 2x^2 - x + 1 = -1, which is three.

  • Setting y = 2 and graphing it with y = x^3 - 2x^2 - x + 1 shows that x^3 - 2x^2 - x + 1 = 2 has only one solution.

Share This Summary 📚

Summarize YouTube Videos and Get Video Transcripts with 1-Click

Download browser extensions on:

Explore More Summaries from Khan Academy 📚

Summarize YouTube Videos and Get Video Transcripts with 1-Click

Download browser extensions on: