Slope of a secant line example 1  Taking derivatives  Differential Calculus  Khan Academy  Summary and Q&A
Slope of a secant line example 1  Taking derivatives  Differential Calculus  Khan Academy
TL;DR
This video explains how to find the slope of a secant line for a curve with the equation y = ln(x), using the points P(e,1) and Q(x, ln(x)).
Questions & Answers
Q: What is the equation of the curve discussed in the video?
The curve has the equation y = ln(x).
Q: What are the coordinates of point P?
Point P has the coordinates (e, 1).
Q: What is the change in x between points P and Q?
The change in x is x  e.
Q: How is the slope of the secant line calculated?
The slope of the secant line is calculated by taking the change in y (ln(x)  1) divided by the change in x (x  e).
Summary & Key Takeaways

The video discusses finding the slope of the secant line of a curve with the equation y = ln(x) using the points P(e,1) and Q(x, ln(x)).

The natural logarithm of x approaches negative infinity as x gets smaller, and the curve passes through the points P and Q.

To find the slope of the secant line, the change in y (ln(x)  1) is divided by the change in x (x  e).
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