Finding derivative with fundamental theorem of calculus: x is on both bounds  Khan Academy  Summary and Q&A
TL;DR
The video explains how to take the derivative of a definite integral using the fundamental theorem of calculus.
Questions & Answers
Q: How can the fundamental theorem of calculus be applied to find the derivative of a definite integral?
In the case where the upper and lower bounds of the integral both contain x, the integral can be split into two separate integrals by introducing a constant, c. This allows us to rewrite the expression in a form that can be evaluated using the fundamental theorem of calculus.
Q: What is the purpose of introducing the constant, c, to split the integral into two separate integrals?
Introducing the constant allows us to break down the overall area under the curve into two distinct areas. This makes it easier to evaluate the integral and apply the fundamental theorem of calculus.
Q: How does the derivative of the first integral, from c to x, differ from the derivative of the second integral, from c to x squared?
The derivative of the first integral is negative cosine(x)/x, while the derivative of the second integral is 2cos(x^2)/x. The first integral contributes a negative term to the final derivative, while the second integral adds a positive term.
Q: Can the result of the derivative be further simplified?
Yes, the final result can be simplified to (x)(2cos(x^2)  cos(x)). By combining like terms and rearranging, we can express the derivative in a more concise form.
Summary & Key Takeaways

The video discusses the process of taking the derivative of a definite integral and how it relates to the fundamental theorem of calculus.

By graphing the function within the integral, it becomes apparent that the integral can be split into two separate integrals using a constant, c.

The final result of the derivative can be simplified to x(2cos(x^2)  cos(x)).