Compound inequalities | Linear inequalities | Algebra I | Khan Academy | Summary and Q&A

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January 25, 2011
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Khan Academy
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Compound inequalities | Linear inequalities | Algebra I | Khan Academy

TL;DR

Learn how to solve compound inequalities by finding the possible values of z that satisfy the given conditions.

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Key Insights

  • 🤪 A compound inequality consists of two conditions that z can satisfy, allowing for multiple possible values.
  • ➗ When dividing or multiplying both sides of an inequality by a negative number, the inequality sign must be swapped.
  • 🤪 The solution set of a compound inequality is determined by finding the values of z that satisfy either one or both conditions.

Transcript

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Questions & Answers

Q: How do you solve the compound inequality 5z + 7 < 27 or -3z ≤ 18?

To solve this compound inequality, we solve each inequality separately. For 5z + 7 < 27, we isolate z and divide both sides by 5. For -3z ≤ 18, we divide both sides by -3 and swap the inequality sign. The solution set is z < 4 or z ≥ -6.

Q: Why do we swap the inequality sign when dividing by a negative number?

When dividing or multiplying both sides of an inequality by a negative number, we swap the inequality sign to maintain the correct order of the inequality. Swapping the sign ensures the solution set remains unchanged.

Q: Can you explain the number line representation of the solution set?

The number line is used to represent the values of z that satisfy the compound inequality. For z < 4, a circle is placed around 4 (excluding it), and all values to the left of 4 are included. For z ≥ -6, a circle is placed around -6 (including it), and all values to the right of -6 are included. The shaded region on the number line represents the solution set.

Q: How can we determine if a specific number satisfies the compound inequality?

To determine if a number satisfies the compound inequality, substitute it into both inequality conditions. If it satisfies either one or both conditions, then it is a valid solution. If it fails to satisfy both conditions, it is not a valid solution. Testing multiple numbers can help confirm the validity of the solution set.

Summary & Key Takeaways

  • A compound inequality consists of two conditions that z can satisfy, where z can satisfy either one or both of them.

  • The first inequality is solved by isolating z and dividing both sides by 5, resulting in z < 4.

  • The second inequality requires dividing both sides by -3 and swapping the inequality sign, resulting in z ≥ -6.

  • The solution set for the compound inequality is z < 4 or z ≥ -6, meaning any value of z less than 4 or greater than or equal to -6 satisfies the conditions.

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