2017 AP Calculus AB/BC 4c | AP Calculus AB solved exams | AP Calculus AB | Khan Academy | Summary and Q&A

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July 31, 2017
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2017 AP Calculus AB/BC 4c | AP Calculus AB solved exams | AP Calculus AB | Khan Academy

TL;DR

This video explains how to solve a separable differential equation to find the internal temperature of a potato at a specific time.

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Questions & Answers

Q: What kind of differential equation is being solved in this video?

This video solves a separable differential equation, which means the variables can be separated on different sides of the equation before integrating.

Q: How is the initial condition used to find the constant value in the expression for the internal temperature?

The initial condition, G(0) = 91, is substituted into the expression and solved for the constant value. In this case, C is found to be equal to 12.

Q: How is the internal temperature of the potato determined at a specific time?

By substituting the time value into the expression for G(T), the video demonstrates how to find the internal temperature of the potato at that time.

Q: What units are used for the internal temperature in this problem?

The internal temperature of the potato is measured in degrees Celsius.

Summary & Key Takeaways

  • The video teaches how to solve a separable differential equation to find an expression for the internal temperature of a potato.

  • The initial condition given in the problem is used to find the constant value in the expression for the internal temperature.

  • By substituting the time value into the expression, the video demonstrates how to determine the internal temperature of the potato at that specific time.

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