# 2017 AP Calculus AB/BC 4c | AP Calculus AB solved exams | AP Calculus AB | Khan Academy | Summary and Q&A

13.4K views
July 31, 2017
by
2017 AP Calculus AB/BC 4c | AP Calculus AB solved exams | AP Calculus AB | Khan Academy

## TL;DR

This video explains how to solve a separable differential equation to find the internal temperature of a potato at a specific time.

## Install to Summarize YouTube Videos and Get Transcripts

### Q: What kind of differential equation is being solved in this video?

This video solves a separable differential equation, which means the variables can be separated on different sides of the equation before integrating.

### Q: How is the initial condition used to find the constant value in the expression for the internal temperature?

The initial condition, G(0) = 91, is substituted into the expression and solved for the constant value. In this case, C is found to be equal to 12.

### Q: How is the internal temperature of the potato determined at a specific time?

By substituting the time value into the expression for G(T), the video demonstrates how to find the internal temperature of the potato at that time.

### Q: What units are used for the internal temperature in this problem?

The internal temperature of the potato is measured in degrees Celsius.

## Summary & Key Takeaways

• The video teaches how to solve a separable differential equation to find an expression for the internal temperature of a potato.

• The initial condition given in the problem is used to find the constant value in the expression for the internal temperature.

• By substituting the time value into the expression, the video demonstrates how to determine the internal temperature of the potato at that specific time.