U Tube Manometers  Pressure, Density & Height of Oil & Water  Fluid Mechanics  Summary and Q&A
TL;DR
The content explains how to determine the height of a fluid column in a Ushaped tube using the concept of equilibrium.
Questions & Answers
Q: How does the pressure in a Ushaped tube remain in equilibrium?
The pressure on the left side is a combination of atmospheric pressure and the weight of the oil, whereas the pressure on the right side is atmospheric pressure and the pressure of the water. Equilibrium is achieved when these pressures are equal.
Q: How is the height of the oil column determined?
The pressure due to the weight of the oil is equal to the pressure due to the weight of the water. By using the equation for pressure, which is density times gravitational acceleration times height, the height of the oil column can be calculated.
Q: What is the density of the oil in a Ushaped tube with water on the right column?
To find the density of the oil, the equation for pressure equating the oil and water heights needs to be used. By rearranging the equation and plugging in the given values, the density of the oil can be determined.
Q: How is the height difference between the oil and water surfaces calculated?
By establishing a reference level and applying the pressure equilibrium equation, the height of the water above the reference level and the height of the oil can be used to calculate the height difference between the two surfaces.
Summary & Key Takeaways

The pressure on the left side of the Ushaped tube is due to atmospheric pressure and the weight of the oil, while the right side has atmospheric pressure and the pressure of the water.

The downward pressure due to the weight of the oil is equal to the downward pressure due to the weight of the water.

By using the equation for pressure due to the weight of a fluid, the height of the oil column can be calculated.