Numerical Based on Decay Constant Problem 13 - Nuclear Chemistry & Radioactivity

TL;DR

Learn how to calculate the percentage of an undecayed sample after a certain period of time for a given radioactive element.

Transcript

click the bell icon to get latest videos from akira help friends in the previous topic we have discussed about a numerical which was based on the decay constant that is problem number 12 and now here basically we are going to talk about the problem number 13 so what is the question and what is the required thing that is we have to calculate let me ... Read More

Key Insights

• ☠️ The half-life of a radioactive element determines the rate at which it decays.
• ❓ The decay constant can be calculated using the formula lambda = 0.693 / T_half.
• 🥳 The formula lambda = 2.303 / (log10(M_naught / N)) allows us to find the ratio of the initial amount of the sample to the remaining amount.

Questions & Answers

Q: What is the half-life of the sulfur-35 sample?

The half-life of the sulfur-35 sample is 87.8 days.

Q: What is the formula for calculating the decay constant?

The formula for calculating the decay constant is lambda = 0.693 / T_half, where T_half is the half-life.

Q: What formula is used to find the ratio of the initial amount of the sample to the remaining amount?

The formula used is lambda = 2.303 / (log10(M_naught / N)), where M_naught is the initial amount and N is the remaining amount.

Q: What is the value of N, the remaining amount of the sample, after 180 days?

The value of N is found to be 24.21, representing 24.21% undecayed sample.

Summary & Key Takeaways

• The problem is to find the percentage of sulfur-35 sample that remains undecayed after 180 days, given its half-life of 87.8 days.

• The decay constant is calculated using the formula lambda = 0.693 / T_half, where T_half is the half-life.

• The formula lambda = 2.303 / (log10(M_naught / N)) is used to find the value of N naught / N, which represents the ratio of the initial amount of the sample to the remaining amount.

• By substituting the values and solving the equation, the value of N is found to be 24.21, representing 24.21% undecayed sample.