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How to Use Logarithmic Differentation to Find dy/dx given y = (sin(x))^(tan(x))

2.4K views
•
December 7, 2020
by
The Math Sorcerer
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How to Use Logarithmic Differentation to Find dy/dx given y = (sin(x))^(tan(x))

TL;DR

Learn how to find dy/dx using logarithmic differentiation simplifying complex expressions step-by-step.

Transcript

hi everyone in this problem we're being asked to find d y d x using something what's called logarithmic differentiation so to use logarithmic differentiation we start by taking the natural log on both sides so we have ln of y equals and then here we have ln of the sine of x to the tangent of x so that's step one in logarithmic differentiation the n... Read More

Key Insights

  • 😑 Logarithmic differentiation involves taking the natural log of an equation to simplify complex expressions.
  • 👻 Property of logs allows for easier handling of challenging functions like sine and tangent in derivatives.
  • 📏 The product rule in calculus is crucial in finding the derivative of functions multiplied together.
  • ❓ Reciprocal relationships between trigonometric functions can simplify derivative calculations.
  • 🤝 Understanding the chain rule is essential when dealing with composite functions in derivatives.
  • 🔨 Logarithmic differentiation is a powerful tool for finding derivatives of complicated functions.
  • 🍉 Final derivative expressions may involve the original function, trigonometric terms, and constant terms.

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Questions & Answers

Q: What is the first step in logarithmic differentiation?

The first step is to take the natural log of both sides of the equation to simplify the expression and prepare for finding the derivative.

Q: How is the product rule used in logarithmic differentiation?

The product rule is applied when finding the derivative of the product of two functions, multiplying the derivative of the first function with the second and vice versa.

Q: Why does the cotangent term simplify to one in the final derivative expression?

The cotangent term simplifies to one because of the reciprocal relationship between cotangent and tangent, cancelling out in the final derivative calculation.

Q: Can you explain the final expression for dy/dx in logarithmic differentiation?

The final expression for dy/dx involves the original function y, secant squared x, the natural log of sine x, and a constant term of one, obtained through logarithmic differentiation.

Summary & Key Takeaways

  • Logarithmic differentiation involves taking the natural log of both sides of an equation.

  • Simplify the expression using logarithmic properties and then take the derivative with respect to x.

  • Utilize the product rule to find the derivative of the product of two functions.


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