NEET Physics Atom : Multiple Choice Previous Years Questions MCQs 3

TL;DR

Examining the ratio of debrie wavelength of incident electrons to the shortest wavelength x-ray produced, calculating the longest wavelengths corresponding to Lyman and bomber series in the hydrogen spectrum, determining the velocity acquired by a hydrogen atom when an electron transitions from the fifth energy level to the ground level, finding the energy of a helium ion in the first excited state, and analyzing the number of lines in the emission spectrum of hydrogen.

Transcript

hello friends this video on meet Adams was brought to you by exam for calm no more fear from exam question number 10 if ten thousand volt is applied across an x-ray tube what will be the ratio of debrie wavelength of the incident electrons to the shortest wavelength x-ray produced charged by mass ratio for electron is 1 point 8 into 10 to the power... Read More

Key Insights

• 📤 The ratio of debrie wavelength to x-ray wavelength in an x-ray tube can be calculated by considering the energy of electrons and x-rays.
• 🎚️ The longest wavelengths in the Lyman and bomber series in the hydrogen spectrum correspond to specific energy level transitions.
• 🫀 The velocity acquired by a hydrogen atom during an electron transition can be determined using the difference in energy levels.
• 🫀 The energy of a helium ion in the first excited state can be calculated using the same formula as for the hydrogen atom, taking into account the atomic number.

Questions & Answers

Q: How is the wavelength of electrons in an x-ray tube calculated?

The wavelength of electrons can be calculated using the deep Roy hypothesis, which states that wavelength is equal to Planck's constant divided by the square root of 2 times the electron energy multiplied by its mass and the speed of light.

Q: What is the ratio of debrie wavelength to x-ray wavelength when a voltage of 10,000 volts is applied?

The ratio is equal to 1 divided by the speed of light, multiplied by the square root of the ratio of electron charge to mass, multiplied by the voltage divided by 2. Putting in the given values, the ratio is calculated to be 0.1.

Q: How can the longest wavelength in the Lyman and bomber series be determined?

The longest wavelength in the Lyman series corresponds to the transition from the second energy level to the first, while in the bomber series, the transition is from the third energy level to the second. Using the formula 1/lambda = R(1/n1^2 - 1/n2^2), the wavelengths can be calculated.

Q: What is the ratio of the longest wavelengths in the Lyman and bomber series?

The ratio of the longest wavelengths in the Lyman and bomber series can be calculated by dividing the wavelength of the Lyman series by the wavelength of the bomber series. The resulting ratio is 5/27.

Summary & Key Takeaways

• The video discusses the ratio of debrie wavelength of incident electrons to the shortest wavelength x-ray produced in an x-ray tube when a voltage is applied.

• It explains how to calculate the longest wavelengths corresponding to the Lyman and bomber series in the hydrogen spectrum.

• The video demonstrates how to find the velocity acquired by a hydrogen atom when an electron transitions from the fifth energy level to the ground level.

• It discusses the energy of a helium ion in the first excited state.

• The video explores the number of spectral lines emitted by hydrogen when excited by monochromatic radiation.