What Is the Relationship Between Breakdown Voltage and Doping Concentration in Diodes?

TL;DR

The breakdown voltage (VBR) in diodes is inversely proportional to the doping concentration (ND), represented by the formula VBR = ε^2 / (2Q * ND). This relationship indicates that as the doping concentration increases, the breakdown voltage decreases, while the product of VBR and ND remains constant.

Transcript

hello friends in this video we are going to discuss about the numerical on previous year question on the electronics device according to the given numerical it is written that consider the Avalanche breakdown in a silicon diode in a P plus n Junction the N region is uniformly doped and breakdown occurs when the electric field is equals to e critica... Read More

Key Insights

• 🏑 Avalance breakdown in diodes occurs when the electric field reaches a critical value.
• ⚡ The relationship between breakdown voltage and doping concentration is given by the equation VB R = ε^2 / (2Q * ND).
• ⚡ The breakdown voltage is inversely proportional to the doping concentration.
• 🏛️ The breakdown voltage is not affected by the diode's built-in potential.
• ⚡ The breakdown voltage is influenced by the electric field and the doping concentration.
• 🛀 The equation shows that the product of breakdown voltage and doping concentration is constant.
• 🔚 The video suggests that the relationship between breakdown voltage (VBR) and doping concentration (ND) can be determined using the equation VBR * ND = constant.

Summary & Key Takeaways

• The video discusses the Avalanche breakdown in a silicon diode in a P plus n Junction.

• It explains how the breakdown voltage (VBR) is related to the doping concentration (ND) in the diode.

• The breakdown voltage is proportional to 1/ND, according to the equation VB R = ε^2 / (2Q * ND).