Power Series Representation With Natural Logarithms - Calculus 2 | Summary and Q&A

TL;DR

The video explains how to find the power series representation of ln(1 - x^2) and discusses its interval of convergence.

Key Insights

• ☺️ ln(1 - x^2) can be factored as ln(1 - x) + ln(1 + x) using the property of natural logarithms.
• ☺️ The derivatives of ln(1 - x) and ln(1 + x) are -1/(1 - x) and 1/(1 + x), respectively.
• ☺️ The power series representation of ln(1 - x^2) can be obtained by combining the series for ln(1 - x) and ln(1 + x).
• ☺️ The interval of convergence for ln(1 - x^2) is (-1, 1), which means the series converges for values of x between -1 and 1.
• ☺️ As the value of x approaches the center of convergence (0), fewer terms are needed to get an accurate approximation.

Transcript

let's say if we have the function ln 1 minus x squared how can we write a power series representation of that function the first thing we need to do is factor one minus x squared and so we can write that as one minus x times one plus x now a property of natural logs allows us to take a single log and express it as a sum of two logs so ln a times b ... Read More

Questions & Answers

Q: How do you factor 1 - x^2 to find the power series representation of ln(1 - x^2)?

To factor 1 - x^2, we can write it as (1 - x)(1 + x). This allows us to express ln(1 - x^2) as ln(1 - x) + ln(1 + x).

Q: What is the derivative of ln(1 - x)?

The derivative of ln(1 - x) is calculated using the chain rule, which gives us -1/(1 - x).

Q: What is the integral of ln(1 + x)?

The integral of ln(1 + x) is determined by substituting u = 1 + x, which transforms it into ln(u). The integral of ln(u) is u(ln(u) - 1) + C.

Q: How is the power series representation of ln(1 - x^2) derived?

By combining the power series representation of ln(1 - x) and ln(1 + x), we obtain the series representation of ln(1 - x^2).

Summary & Key Takeaways

• The video demonstrates how to factor 1 - x^2 and rewrite ln(1 - x^2) as ln(1 - x) + ln(1 + x).

• The derivative of ln(1 - x) is -1/(1 - x), and the derivative of ln(1 + x) is 1/(1 + x).

• The video shows the integral of the series representation of ln(1 - x) and ln(1 + x).

• The power series representation of ln(1 - x^2) is derived by combining the series for ln(1 - x) and ln(1 + x).

• The final representation of ln(1 - x^2) is given as a series using the coefficients of x^2n/(2n+2).