Gauss Law Problems, Insulating Sphere, Volume Charge Density, Electric Field, Physics

TL;DR

An insulating sphere with a radius of 2 meters and a charge of 50 micro coulombs has an electric field of 84,375 newtons per coulomb 1.5 meters away from its center.

Transcript

an insulating sphere of radius 2 meters contains 50 micro coulombs of electric charge uniformly distributed throughout the volume of the sphere what is the electric field 1.5 meters away from the center of the sphere how can we do this well let's begin by drawing a picture so this is going to be the sphere and it's going to have a radius which we'l... Read More

Key Insights

• 🏑 Conducting spheres have charge distributed on the surface, resulting in no electric field inside.
• 🈶 Gauss's law allows for the calculation of the electric field using the charge enclosed and the permittivity of free space.
• 😉 The electric field inside an insulating sphere is given by the formula E = (k * Q * r) / (R^3).
• 🔇 The volume charge density (ρ) can be calculated using the equation ρ = Q / (4/3 * π * R^3).

Summary & Key Takeaways

• An insulating sphere with a radius of 2 meters contains a uniformly distributed charge of 50 micro coulombs throughout its volume.

• The electric field is calculated using Gauss's law, which states that the electric flux is equal to the charge enclosed divided by the permittivity of free space.

• The formula for the electric field inside the sphere is E = (k * Q * r) / (R^3), where k is a constant, Q is the total charge, r is the radius of the gaussian surface, and R is the radius of the sphere.