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Initial Value Problem dy/dx = (y - 1)/(x + 3) with y(-1) = 0 Separable Differential Equation

26.1K views
•
September 7, 2018
by
The Math Sorcerer
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Initial Value Problem dy/dx = (y - 1)/(x + 3) with y(-1) = 0 Separable Differential Equation

TL;DR

Solving a separable differential equation with initial condition by integration and finding the constant.

Transcript

every once in this problem we have an initial value problem so we have a differential equation and the initial condition we have to find the solution to the differential equation so this appears to be a separable differential equation what that means is you can separate it so you can write stuff with why do you.why on one side equals stuff with xdx... Read More

Key Insights

  • ❓ Initial value problems involve solving differential equations with given initial conditions.
  • ❓ Separable differential equations can be solved by integrating the separated variables.
  • ❓ Finding the constant in the solution requires using the initial condition provided in the problem.
  • ❓ Basic integration techniques are crucial in solving initial value problems efficiently.
  • 😑 Substituting variables and simplifying expressions lead to the final solution.
  • ❓ Familiarity with differential equations and integration is essential in solving such mathematical problems effectively.
  • ❓ Renaming constants can sometimes make the problem-solving process more manageable.

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Questions & Answers

Q: How do you start solving an initial value problem with a differential equation?

To begin, identify the type of differential equation, in this case, a separable one, and separate the variables by writing dy/(y-1) = dx/(x+3).

Q: What is the next step after separating the variables in the differential equation?

The next step involves integrating both sides of the equation, which can be done straightforwardly in this case due to the simple form of the integrals involved.

Q: How is the constant determined when solving an initial value problem?

The constant is found by using the initial condition provided in the problem and substituting the values to solve for the constant value, which is crucial for the final solution.

Q: How is the final solution obtained in an initial value problem with a differential equation?

By integrating both sides, determining the constant with the initial condition, and simplifying the expression to find the solution in terms of the variables involved.

Summary & Key Takeaways

  • Demonstrates solving a separable differential equation with initial condition.

  • Utilizes basic integration techniques to find the solution.

  • Determines the constant value using the initial condition provided.


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