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Improper integral of 1/x from -1 to 1 (THE DEBATE?)

290.7K views
•
June 22, 2018
by
blackpenredpen
YouTube video player
Improper integral of 1/x from -1 to 1 (THE DEBATE?)

TL;DR

The video discusses the debate surrounding the integral from -1 to 1 of 1/x, presenting two interpretations and concluding that it is a divergent integral.

Transcript

that's why I purposely let a bigger gap from 0 minus to 0 today I'm going to discuss the debate of this integral from negative 1 to 1 of 1 over X DX with you guys and the reason I say this is the debate because it seems like there are two ways to interpret this integral and it seems that they are two answers as well so I will demonstrate both and a... Read More

Key Insights

  • ☺️ There are two interpretations of the integral from -1 to 1 of 1/x, one based on the properties of odd functions and symmetrical integrals, and the other as an improper integral.
  • ☺️ The first interpretation suggests the integral is zero, but it relies on the function being continuous, which is not the case for 1/x due to the vertical asymptote at x=0.
  • 🥳 The second interpretation splits the improper integral into two parts, taking into account the vertical asymptote and evaluating each separately.
  • 🙃 The limits in the notation of the improper integral indicate the approach towards the point of divergence at x=0 from both sides.
  • ☺️ The practice of using absolute value in the antiderivative of 1/x is necessary to consider the possibility of negative values of x.
  • ☺️ The graph of 1/x shows that as x approaches zero from different sides, the function goes to positive and negative infinity, supporting the divergent interpretation.
  • ♾️ The indeterminate form of infinity minus infinity arises in the computation of the integral, indicating that the two areas do not cancel each other out.

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Questions & Answers

Q: How can the integral from -1 to 1 of 1/x be interpreted as a value of zero?

The first interpretation considers the function being odd and the integral being symmetrical, resulting in the cancellation of positive and negative areas, leading to a value of zero.

Q: Why does the improper integral need to be split into two parts?

The improper integral needs to be split because the function has a vertical asymptote at x=0, which makes the integral undefined at that point. By breaking it into two parts, one from -1 to 0 and another from 0 to 1, we can evaluate each separately.

Q: What is the significance of using the limits in the notation of the improper integral?

The limits in the notation of the improper integral indicate that we are approaching the point of divergence (x=0) from both the left and right sides. It allows us to consider the behavior of the function at that point.

Q: How does the graph of 1/x help in understanding the two interpretations?

The graph of 1/x shows that as we approach x=0 from the left and right sides, the function goes to negative and positive infinity respectively. This supports the understanding of the integral as divergent.

Summary & Key Takeaways

  • The integral from -1 to 1 of 1/x can be interpreted in two ways: as an odd function resulting in a value of zero, or as an improper integral that needs to be split into two parts.

  • The first interpretation considers the symmetrical nature of the integral and the function being odd, leading to a value of zero.

  • The second interpretation acknowledges the vertical asymptote at x=0 and splits the integral into two improper integrals, which results in a divergent integral.


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