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Maths Algebra part 8 (Questions) CBSE Class 6 Mathematics VI

December 31, 2016
by
LearnoHub - Class 11, 12
YouTube video player
Maths Algebra part 8 (Questions) CBSE Class 6 Mathematics VI

TL;DR

This video explains how to calculate the perimeter of a regular hexagon, the diameter of a circle in terms of its radius, and how to express one person's age in terms of another person's age.

Transcript

hello friends this video on algebra part 8 is brought to you by exam feel calm no more fear from exam so based on whatever we have learned so far we will look at some questions question number 1 the side of a regular hexagon is denoted by L express the perimeter of the hexagon using L so what is the meaning of parameter so perimeter is nothing but ... Read More

Key Insights

  • ✖️ The perimeter of a regular hexagon is calculated by multiplying the length of one side by 6.
  • 🟰 The diameter of a circle is always equal to twice the radius.
  • 🤵 Expressing one person's age in terms of another person's age can be done by subtracting the age difference.

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Questions & Answers

Q: How is the perimeter of a regular hexagon calculated?

The perimeter of a regular hexagon is equal to 6 times the length of one side.

Q: What is the relationship between the diameter and radius of a circle?

The diameter of a circle is always equal to twice the value of the radius.

Q: How can Leela's age be expressed in terms of Raja's age?

Leela's age can be calculated as Raja's age minus 4, since she is 4 years younger than Raja.

Q: How can the number of oranges in the larger box be determined?

The number of oranges in the larger box can be found by adding the number of oranges in the smaller boxes (represented by X) and the remainder (10), resulting in 2X + 10.

Summary & Key Takeaways

  • The perimeter of a regular hexagon can be expressed as 6 times the length of one side.

  • The diameter of a circle is always equal to twice the radius.

  • Leela's age, who is 4 years younger than Raja, can be expressed as Raja's age minus 4.

  • When transferring oranges from a large box to smaller boxes, the number of oranges in the large box can be determined using the number of oranges in the smaller boxes and the remainder.


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