Problem on Calculation of Power Transmitted Through Diameter Shaft

TL;DR

Calculate the maximum power that can be transmitted through a 50mm diameter shaft at 150 rpm given a maximum permissible shear stress of 80 N/mm².

Transcript

let us take the next question find the maximum power that can be transmitted through a 50 mm diameter shaft at 150 rpm if maximum permissible shear stress is 80 newton per mm square again we have a question here let us try to write the data first here the question is find the maximum power so capital p is what we have to calculate that can be trans... Read More

Key Insights

• ✊ The maximum power transmitted through a shaft can be calculated using the equation P = (2πnT) / 60.
• 🇹🇯 Torque is determined using the strength criteria formula T/j = fs/r.
• ☺️ In this problem, the torque value is calculated as 1.963 x 10^3 Nm.
• ✊ The calculated power for this problem is 30.84 kW.
• 🤩 Speed, torque, and maximum permissible shear stress are key factors in determining the maximum power transmitted through a shaft.
• ❓ The diameter of the shaft is an essential parameter for calculating torque.
• 🖐️ Polar moment of inertia and radius play roles in the calculation of torque.

Questions & Answers

Q: What is the equation for power transmitted by a shaft?

The equation for power transmitted by a shaft is P = (2πnT) / 60, where P is power, n is the speed in rpm, and T is torque.

Q: How is torque determined in this problem?

Torque is determined using the strength criteria formula T/j = fs/r, where T is torque, j is polar moment of inertia, fs is maximum permissible shear stress, and r is radius.

Q: What is the value of torque calculated in this problem?

The calculated value of torque is 1.963 x 10^3 Nm after converting from 1.963 x 10^6 Nmm.

Q: How is the power calculated in this problem?

The power is calculated by substituting the given values of speed (150 rpm) and torque (1.963 x 10^3 Nm) into the equation P = (2πnT) / 60, resulting in a power of 30.84 kW.

Summary & Key Takeaways

• The question requires finding the maximum power that can be transmitted through a 50mm diameter shaft at 150 rpm.

• The maximum permissible shear stress is given as 80 N/mm².

• Using the equation for power transmitted by a shaft, the torque is calculated and then used to find the power.