Computer Organization & Architecture (GATE CSE) - Control Unit - 30 Oct, 6 PM | Summary and Q&A

TL;DR

This content provides insights on solving gate questions related to instruction set architecture in a 16-bit architecture system.

Key Insights

• 😫 Understanding the composition of a 16-bit instruction helps in solving gate questions on instruction set architecture.
• 📳 The mode digit determines the addressing mode, with 0 representing direct addressing and 1 representing indirect addressing.
• #️⃣ The number of opcodes and registers affects the number of digits allotted to their respective fields.
• 🏑 The size of the immediate operand field determines the maximum size of the immediate operand.

Transcript

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Questions & Answers

Q: How are the 16 bits of the instruction divided into different fields?

The instruction is divided into the mode digit, opcode (3 digits), and address of the operand (12 digits).

Q: How many opcodes are possible in the instruction set?

There are a total of 8 opcodes possible in the instruction set.

Q: What is the maximum size of the immediate operand?

The immediate operand field is 16 bits, allowing for a maximum size of 2^16 or 64k.

Q: How is the size of the main memory determined?

The size of the main memory is determined by the number of digits allotted for the address of the operand, which is 12 digits in this case.

Summary & Key Takeaways

• The instructor discusses the composition of a 16-bit instruction, including the mode digit, opcode, and address of the operand.

• The total number of opcodes is 8, and each combination represents one opcode.

• The address of the operand is 12 digits, representing a range of 2^12.

• The instructor presents example questions and solutions for determining the number of bits in the immediate operand and the maximum size of the operand.