NEET Physics Atom : Multiple Choice Previous Years Questions MCQs 6 | Summary and Q&A

TL;DR
This video explains various concepts related to X-ray tube and atom, including potential difference, diffraction, intensity, and wavelength.
Key Insights
- đ¤ Increasing the potential difference in an X-ray tube increases the kinetic energy of electrons and requires a thicker foil.
- đŠī¸ X-rays have a shorter wavelength than visible light, resulting in a smaller diffraction disk.
- đ¤ The intensity of X-rays remains unchanged when the potential difference in an X-ray tube is increased.
Transcript
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Questions & Answers
Q: What happens to the thickness of the aluminum foil in an X-ray tube when the potential difference is increased?
As the potential difference is increased, the kinetic energy of the electrons hitting the target increases, requiring a thicker aluminum foil to allow the electrons to come to rest.
Q: How does the radius of the diffraction disk formed by X-rays differ from visible light?
X-rays have a shorter wavelength than visible light, so the radius of the diffraction disc formed by X-rays would be smaller than that of visible light.
Q: What happens to the minimum wavelength and intensity when the potential difference in an X-ray tube is increased?
Increasing the potential difference in an X-ray tube decreases the minimum wavelength of the emitted X-rays. However, the intensity remains unchanged.
Q: How can the electric field between the cathode and target in an X-ray tube be calculated?
By using the given cutoff wavelength and distance between the filament and target, the energy of the radiation can be calculated. From there, the potential difference can be determined, and dividing it by the distance gives the electric field.
Summary & Key Takeaways
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Varying the potential difference in an X-ray tube increases the kinetic energy of electrons, requiring a thicker aluminum foil as the electrons need more distance to come to rest.
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When X-rays are passed through a setup that previously produced visible light, the radius of the diffraction disk is decreased due to X-rays having a shorter wavelength.
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Increasing the potential difference in an X-ray tube decreases the minimum wavelength of the emitted X-rays, while the intensity remains unchanged.
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Using the given cutoff wavelength and distance between the filament and target in an X-ray tube, the electric field between the cathode and target can be calculated.
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