Find dy/dt when given dx/dt Related Rates | Summary and Q&A

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February 21, 2020
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The Math Sorcerer
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Find dy/dt when given dx/dt Related Rates

TL;DR

The content discusses the process of taking derivatives and solving for dy/dt using given conditions and equations.

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Key Insights

  • 🫑 Taking the derivative with respect to T is essential when finding dy/dt.
  • ☺️ Conditions such as X = 8 and DX/DT = 13 provide specific values for calculation.
  • 🐞 Solving for Y is necessary to substitute it into the equation for dy/dt.
  • ❓ The calculation involves several steps and computations.
  • ❓ The process requires manipulating equations and algebraic simplification.
  • 🐞 The values of X, DX/DT, and Y are used to plug into the equation for dy/dt.
  • πŸ‰ Subtracting terms and simplifying fractions are common operations in the calculation.

Transcript

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Questions & Answers

Q: How is the derivative of the first term calculated when finding dy/dt?

The derivative of the first term is found by multiplying it with the derivative of the second term when taking the derivative with respect to T.

Q: What is the significance of the conditions X = 8 and DX/DT = 13 in the calculation?

The conditions X = 8 and DX/DT = 13 are used to provide specific values for X and DX/DT, which are necessary to solve for dy/dt.

Q: Why is finding Y necessary in the process of solving for dy/dt?

Finding Y is necessary because the equation for dy/dt includes Y. By substituting the value of X and simplifying the equation, Y can be calculated and plugged into the equation.

Q: How is the value of dy/dt determined in the video?

The value of dy/dt is determined by solving the equation 13/4 + 8(dy/dt) = 0, where the given values of X, DX/DT, and Y are substituted.

Summary & Key Takeaways

  • The video explains the process of taking the derivative with respect to T in order to find dy/dt.

  • The derivative of the first term is calculated by multiplying it with the derivative of the second term.

  • The video demonstrates how to solve for dy/dt using the given conditions and equations.

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