NEET Biology Genetics : Multiple Choice Previous Years Questions MCQs 1 | Summary and Q&A

106.1K views
March 30, 2017
by
LearnoHub - Class 11, 12
YouTube video player
NEET Biology Genetics : Multiple Choice Previous Years Questions MCQs 1

TL;DR

A detailed explanation of colorblindness inheritance, including genotypes, gametes, and the percentage of male children who would be colorblind.

Install to Summarize YouTube Videos and Get Transcripts

Questions & Answers

Q: What is the genotype of a man whose father was colorblind?

The genotype of the man would be XH Y, as the father being colorblind does not impact the son's genotype.

Q: What is the genotype of a woman with a normal father and a colorblind mother?

The genotype of the woman would be XH XE, as both defective genes are required for colorblindness, and the father is normal.

Q: What are the possible gametes formed when the man (XH Y) and the woman (XH XE) get married?

The possible gametes would be XH X, XH XE, XE Y, resulting in the possible genotypes of the children being XH X, XE X, XH Y.

Q: What percentage of the male children of this couple would be colorblind?

Out of the two male children, one would be colorblind, resulting in a 50% chance.

Summary & Key Takeaways

  • The content explains the question of what percentage of male children of a man with a colorblind father and a woman with a colorblind mother would be colorblind.

  • It breaks down the genotype of the man and the woman, showing that the man would be normal (XH Y) and the woman would be a carrier (XH XE).

  • Through Punnett squares, it shows that out of two male children, one would be colorblind, resulting in a 50% chance.

Share This Summary 📚

Summarize YouTube Videos and Get Video Transcripts with 1-Click

Download browser extensions on:

Explore More Summaries from LearnoHub - Class 11, 12 📚

Summarize YouTube Videos and Get Video Transcripts with 1-Click

Download browser extensions on: