Numerical on Induced Voltage - Part 2 - Synchronous Machine - Electrical Machines - IV | Summary and Q&A

TL;DR

In this analysis, we solve numerical problems related to induced voltage in three-phase generators and calculate the voltage generated by the machine.

Key Insights

• 🇵🇭 The voltage generated by an alternator can be calculated using the formula: eph = root 2 pi f phi nse kp kd.
• 🍰 Short pitching in an alternator winding helps in reducing harmonic content and improving waveform shape.
• 🤨 The useful flux per pole in an alternator can be calculated using the formula: flux = eph / (root 2 pi f nse kp kd).
• ⚡ Phase voltage is the voltage between one phase and the neutral point, while line voltage is the voltage between two phases in a star-connected system.

Transcript

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Questions & Answers

Q: How do we calculate the voltage generated by a three-phase six-pole alternator?

To calculate the voltage generated, we need to use the formula: eph = root 2 pi f phi nse kp kd, where f is the frequency, phi is the flux per pole, nse is the number of series turns, and kp and kd are the winding factor and distribution factor, respectively. Substitute the given values and calculate the result.

Q: What is the significance of short pitching in an alternator winding?

Short pitching refers to the placement of one coil side in a different slot than the other coil side. It helps in reducing harmonic content and improving the waveform shape of the generated voltage.

Q: How do we calculate the useful flux per pole in an alternator?

To calculate the useful flux per pole, we can use the formula: flux = eph / (root 2 pi f nse kp kd). Substitute the given values and calculate the result.

Q: What is the difference between phase voltage and line voltage in a three-phase generator?

Phase voltage refers to the voltage between one phase and the neutral point, while line voltage refers to the voltage between two phases. In a star-connected system, the line voltage is equal to the phase voltage multiplied by the square root of 3.

Summary & Key Takeaways

• We are given data including the number of poles, RPM, number of slots, conductors per slot, and flux value, and we need to calculate the voltage generated by the machine.

• The first problem involves a three-phase six-pole alternator revolving at 1000 RPM, and we calculate the voltage generated based on the winding factor and other given data.

• The second problem involves a six-pole alternator rotating at 1000 RPM with a single-phase winding housed in three slots per pole. We calculate the useful flux per pole required to generate a line voltage of 6000V.