# Triangle Question 4 || 9&10 Math Capsule || Misbah Sir || Infinity Learn Class 9&10 | Summary and Q&A

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June 3, 2023
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Infinity Learn NEET
Triangle Question 4 || 9&10 Math Capsule || Misbah Sir || Infinity Learn Class 9&10

## TL;DR

Angle aqp in triangle ABC is equal to 5/7π radians.

## Key Insights

• 🔙 The given triangle ABC has AB = AC, and points P and Q are located on sides AC and AB, respectively.
• 🟰 Angles opposite to equal sides of a triangle are equal.
• 🔺 The exterior angle property can be used to find angle aqp in terms of the given angles.
• 🔺 The angle sum property is applicable in triangle ABC to find the relationship between angles x, aqp, and y.
• 😀 By substituting y = 3x into the equation, the value of angle aqp can be calculated.

## Transcript

so here we have got a question in which it is given that there is a triangle ABC in which a b is equal to AC and these things are given now we have to find basically angle aqp in terms of Pi where Pi is equal to 180 degrees in radian you know that already right so if I assume that this angle is X so this will also be X because angles opposite to eq... Read More

### Q: How are angles opposite to equal sides of a triangle related?

In a triangle, angles opposite to equal sides are equal. This property helps determine that if angle x is equal, angle aqp will also be x.

### Q: How can the exterior angle property be used in this problem?

Applying the exterior angle property, if angle x is x, then angle aqp is equal to 2x. Similarly, if angle x is 2x, then angle aqp becomes 4x.

### Q: How can the angle sum property be used to solve this problem?

In triangle ABC, using the angle sum property, the sum of angles x, aqp, and y is equal to 180°. Simplifying the equation will result in y = 3x.

### Q: How is angle aqp calculated in terms of π?

By substituting 3x = y and rearranging the equation, we can find that angle aqp is equal to 5/7π.

## Summary & Key Takeaways

• There is a triangle ABC where AB = AC and other specific measurements are given.

• Points P and Q are on sides AC and AB respectively, with BC = BP = QP = AQ.

• The goal is to find the measure of angle aqp in terms of π.