# Laplace Transform of the Convolution of t^2 and te^t | Summary and Q&A

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October 7, 2020
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The Math Sorcerer
Laplace Transform of the Convolution of t^2 and te^t

## TL;DR

The Laplace transform of the convolution of t squared and t * e to the t is (2/(s^3)) * (1/((s-1)^2)).

## Key Insights

• 👻 The convolution theorem allows us to calculate the Laplace transform of the convolution by taking the product of the Laplace transforms of the individual functions.
• ❎ The Laplace transform of t squared is given by 2/(s^3).
• 😃 By applying the first translation theorem, we can simplify the Laplace transform of t * e to the t and introduce a shift in the variable s.
• ❎ The final expression for the Laplace transform of t squared * t * e to the t is (2/(s^3)) * (1/((s-1)^2)).
• 😃 Memorizing the formula for the Laplace transform of t to the power of n as n factorial divided by s^(n+1) can make calculations easier.
• 😑 The shift in the Laplace transform expression is only applicable to the part of the function that includes the exponential term, ensuring accuracy in the calculation.
• 😑 Expressing the Laplace transform as a single fraction simplifies the final answer.

## Transcript

in this problem we have to find the laplace transform of the convolution so we have the laplace of the convolution of the functions t squared and t times e to the t so there's something called the convolution theorem which says whenever you do this all you have to do is compute the product of the laplace transforms this is the laplace of t squared ... Read More

### Q: What is the formula for the Laplace transform of t to the power of n?

The formula states that the Laplace transform of t to the power of n is equal to n factorial divided by s^(n+1).

### Q: How do we handle the Laplace transform of t * e to the t?

We can apply the first translation theorem, which allows us to drop the exponential and replace it with a shift of s to s-1. This is done because there is a coefficient of 1 present in the function.

### Q: What is the purpose of the convolution theorem in Laplace transforms?

The convolution theorem states that the Laplace transform of the convolution of two functions is equal to the product of their individual Laplace transforms.

### Q: How can the Laplace transform expression be simplified for the convolution t squared * t * e to the t?

By simplifying the individual Laplace transforms and applying the shifting theorem, the Laplace transform expression can be written as (2/(s^3)) * (1/((s-1)^2)).

## Summary & Key Takeaways

• The Laplace transform of t squared is 2/(s^3).

• The Laplace transform of t * e to the t involves using the first translation theorem to shift the variable s to s-1.

• The Laplace transform of the convolution t squared * t * e to the t is (2/(s^3)) * (1/((s-1)^2)).