# Inverse Laplace Transform with Partial Fractions Cover-Up Method | Summary and Q&A

11.0K views
June 10, 2015
by
The Math Sorcerer
Inverse Laplace Transform with Partial Fractions Cover-Up Method

## TL;DR

The video explains how to find the inverse Laplace transform of a complex equation using the cover-up method.

## Key Insights

• 😑 Partial fractions are used to decompose a complex expression into simpler fractions.
• 📔 The cover-up method simplifies the calculation of coefficients in partial fractions.
• ❓ The inverse Laplace transform is a mathematical operation that retrieves the original function from its Laplace transform.
• 👻 The inverse Laplace transform is linear, allowing each fraction to be treated separately.
• 🍉 The coefficients found using the cover-up method determine the exponential terms in the final answer.
• 📔 The cover-up method significantly reduces the complexity of solving for the inverse Laplace transform.
• 🧑‍🏭 The procedure demonstrated in the video can be applied to equations with distinct linear factors.

## Transcript

find the inverse Laplace transform of s all being divided by s minus 1 s minus 2 and s minus 3 solution and this problem we will use partial fractions so we'll have s over s minus 1 and then s minus 2 and then as minus 3 and we have distinct linear factors so this is a over s minus 1 plus B over s minus 2 plus C over s minus 3 there's a couple diff... Read More

### Q: What method is used to find the inverse Laplace transform in the video?

The video uses the cover-up method, which involves covering up the linear factor causing the bottom to be zero and plugging in the corresponding values to find the coefficients.

### Q: How are the coefficients calculated in the partial fractions method?

The coefficients are found by covering up the linear factors causing the bottom to be zero and evaluating the equation by plugging in specific values for s.

### Q: What is the purpose of the cover-up method?

The cover-up method simplifies the calculation of coefficients in partial fractions by allowing one to ignore the linear factor that makes the bottom zero and focus on the other terms.

### Q: How is the final answer obtained after finding the coefficients?

The final answer is obtained by taking the inverse Laplace transform of each fraction separately, using the property that the inverse Laplace transform of 1/(s - a) is e^(at).

## Summary & Key Takeaways

• The video demonstrates the process of solving for the inverse Laplace transform using partial fractions.

• The cover-up method is utilized to find the coefficients for each fraction.

• The final answer is obtained by taking the inverse Laplace transform of each fraction.