How to Evaluate a Cubic Function  Summary and Q&A
TL;DR
This video provides stepbystep instructions on how to evaluate a cubic function using specific values.
Key Insights
 ☺️ Evaluating a cubic function involves substituting specific xvalues into the function equation.
 The order of operations, including parentheses and exponentiation, is crucial when calculating the values.
 ❣️ The evaluations for different values of x can result in various yvalues, revealing the behavior of the cubic function.
 🦻 Evaluating functions helps understand how the function behaves for different inputs, aiding in further analysis and problemsolving.
 #️⃣ The given cubic function is a polynomial equation with a degree of 3, and its evaluations produce real number outputs.
 ☺️ The process of evaluating a cubic function can be extended to any given xvalue using the same principles shown in the video.
 👻 Evaluating functions is an essential skill in mathematics, as it allows for the understanding and analysis of various mathematical problems.
Transcript
in this video we're going to do an example of evaluating a cubic function our function is f of x equals X cubed minus 2x squared plus 2X minus 4. and the question is to find F of 0 F of 1 f of negative 1 and F of 2. let's carefully work through this solution let's start with f of zero so F of 0 means we want to evaluate our function f at the x valu... Read More
Questions & Answers
Q: How do you evaluate f(0) for the given cubic function?
To evaluate f(0), substitute 0 for x in the function. This results in f(0) = 0^3  2(0^2) + 2(0)  4, which simplifies to 4.
Q: What is the value of f(1) for the cubic function?
By replacing x with 1 in the function, we get f(1) = 1^3  2(1^2) + 2(1)  4. Simplifying further, f(1) equals 3.
Q: How can f(1) be evaluated using the given cubic function?
Replace each x in the function with 1, considering the negative sign carefully. This yields f(1) = (1)^3  2(1)^2 + 2(1)  4. Simplifying, we find that f(1) equals 9.
Q: What is the value of f(2) for the cubic function provided?
Substituting 2 for x in the function gives f(2) = 2^3  2(2^2) + 2(2)  4, which simplifies to 0.
Summary & Key Takeaways

The video demonstrates how to evaluate a cubic function, f(x) = x^3  2x^2 + 2x  4, for the values f(0), f(1), f(1), and f(2).

By substituting the given x values into the cubic function, the corresponding yvalues are calculated.

The evaluations for f(0), f(1), f(1), and f(2) are 4, 3, 9, and 0, respectively.