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Integral of ln(x)/x^2, integration by parts, DI method

131.5K views
•
February 21, 2016
by
blackpenredpen
YouTube video player
Integral of ln(x)/x^2, integration by parts, DI method

TL;DR

This video explains how to integrate ln x over x^2 using integration by parts.

Transcript

we are going to integrate ln x over x to the  second power and this questions we need to use   integration by parts and of course we will do it  with di setup we are going to pick something to be   differentiated and then something to be integrated  and don't forget when you have the plus minus plus   minus on the side this is the set up we have tw... Read More

Key Insights

  • 🥳 Integration by parts involves choosing functions to differentiate and integrate.
  • ❓ The choice of functions can impact the complexity of the integration process.
  • ☺️ Integrating 1 over x^2 simplifies the overall process of integrating ln x over x^2.
  • 🤨 The final answer includes both a product of a row and a separate integral.

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Questions & Answers

Q: How can integration by parts be used to integrate ln x over x^2?

Integration by parts involves choosing two functions to differentiate and integrate. In this case, we choose to integrate 1 over x^2 and differentiate ln x.

Q: Why is it not ideal to integrate ln x directly?

Integrating ln x directly requires the use of integration by parts. By choosing to integrate 1 over x^2 instead, we can simplify the process.

Q: What is the result of integrating 1 over x^2?

Integrating 1 over x^2 results in -1 over x. This can be obtained by adding 1 to the exponent, which gives x^(-1), and dividing by the new exponent (-1).

Q: How is the final answer for the integration of ln x over x^2 determined?

The final answer is obtained by multiplying the two parts of the integration by parts result and adding a constant term (+ C).

Summary & Key Takeaways

  • The video demonstrates the process of integrating ln x over x^2 using integration by parts.

  • The choice of functions to be differentiated and integrated is discussed.

  • The final result of the integration is provided, with the inclusion of a constant term.


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