Interference Due to a Parallel Flim,Thin Flims | Summary and Q&A

TL;DR
This video explains the interference in thin films due to reflected light and provides equations to calculate fringe width.
Key Insights
- 🎥 Interference in thin films occurs due to reflections and transmissions at different points in the film.
- 😏 The path difference can be calculated using the equation Delta = 2muTcos(r), where Delta is the path difference, mu is the refractive index, T is the thickness of the film, and r is the angle of refraction.
- 🟰 Constructive interference occurs when the path difference is an integral multiple of the wavelength (nλ), and destructive interference occurs when the path difference is equal to (2n+1)λ/2.
Transcript
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Questions & Answers
Q: What is the main focus of this video?
This video focuses on explaining the interference in thin films due to reflected light and provides equations for calculating the fringe width.
Q: How is the path difference calculated in the interference pattern?
The path difference is calculated using the equation Delta = 2muTcos(r), where mu is the refractive index, T is the thickness of the thin film, and r is the angle of refraction.
Q: What are the conditions for constructive interference?
The condition for constructive interference is when the path difference is an integral multiple of the wavelength (nλ), as given by the equation 2muTcos(r) = (2n-1)λ/2.
Q: What are the conditions for destructive interference?
The condition for destructive interference is when the path difference is equal to (2n+1)λ/2, as given by the equation 2muTcos(r) = nλ.
Summary & Key Takeaways
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The video discusses the interference in a thin film due to reflected light and focuses on finding the fringe width in the interference pattern.
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It explains the ray diagram and the partial reflection and transmission that occur at different points.
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The video derives equations for the path difference and discusses the conditions for constructive and destructive interference.
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