IIT JEE Perpendicular Planes (Part 1) | Summary and Q&A

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December 13, 2010
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IIT JEE Perpendicular Planes (Part 1)

TL;DR

This video explains how to find the equation of a plane that contains a given line and is perpendicular to another plane.

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Q: How can the equation of a plane containing a given line and perpendicular to another plane be found?

To find the equation of such a plane, we can find a normal vector by taking the cross product of vectors defined by the given line. Then, we use the normal vector and another arbitrary vector on the plane to determine the equation of the plane.

Q: Why is it necessary to find a normal vector to the plane that contains the given line?

Finding a normal vector is crucial because the dot product of the normal vector and any arbitrary vector on the plane must be equal to zero. This condition allows us to determine the equation of the plane.

Q: How can we find the normal vector to the plane containing the given line?

By taking the cross product of two vectors defined by the given line, we can obtain a vector that is perpendicular to the plane in question. This vector provides the necessary normal vector for finding the equation of the plane.

Q: What information is needed to find the equation of the plane?

In order to find the equation of the plane, we need the equation of the line contained in the plane, the position vector of a point on the line, and an arbitrary vector on the plane.

Summary & Key Takeaways

• The video focuses on finding the equation of a plane that contains a given line and is perpendicular to another plane.

• The position vectors (0, 0, 0) and (2, 3, 4) lie on the plane, which also contains the vector 2i + 3j + 4k.

• By taking the cross product of vectors defined by the given line, the video demonstrates how to find a normal vector that is perpendicular to the plane in question.